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2 years ago

A water sample is found to contain 59 ppm

Chemistry

1 answer:

NeX [460]2 years ago

8 0

Explanation:

k so basically u gotta do 59/1000000 then multiply that by 972 which gives u 0.057348

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A cylinder contains 4.0 g of nitrogen gas. A piston compresses the gas to half its initial volume. Afterward, by what factor has

notka56 [123]

Answer:

The mass density will be doubled

Explanation:

Density is given by dividing the mass of a substance by its volume.
An increase in mass causes an increase in density and vice versa, while a decrease in volume causes an increase in density and volume.
Therefore, when the volume is halved, then the density will be doubled if the mass is kept constant.
This has no effect on the number of moles as the mass is constant.

8 0

2 years ago

Which statement about forces is true?

Elodia [21]

Answer:

Explanation:

because forces act on an object and make it change direction based upon strength hope this helps.

4 0

2 years ago

Pls help :)

prisoha [69]

Answer:

0.484 mole

Explanation:

1 mole of glucose reacts with 6 moles of O2, producing :

6 moles of CO2

6 moles of H2O

678 kcal

Using rule of three you have:

1 mole of glucose -> 678 kcal

x mole of glucose -> 328 kcal

x = 328/678 * 1 =0.484 mole

6 0

3 years ago

The isotope labeling an atom containing 40 protons and 51 neutrons suddenly has two neutrons added to it. What isotope is create

marishachu [46]

I believe the correct answer from the choices listed above is option 2. The isotope of an atom that contains 40 protons and 51 neutrons and suddenly has two neutrons added to it would be Zirconium-93. We look at a periodic table and find the element with the atomic number 40 which equal the number of protons.

8 0

2 years ago

Calculate the amount in grams of Na2CO3 needed to react with HCL to produce 120g NaCl

worty [1.4K]

Let's start off with the balanced chemical equation:

$Na_2CO_{3_{(s)}} + \textbf2HCl_{_{(aq)}}\rightarrow CO_{2_{(g)}} + H_2O_{_{(l)}} + \textbf2NaCl_{_{(aq)}}$

Assuming the sodium carbonate is the limiting reagent, look at the coefficients of sodium carbonate and sodium chloride and use those as a ratio of sodium carbonate to sodium chloride: 1:2.

Since you have the required mass of NaCl, convert this to moles.

Assuming you know how to find the molar mass of NaCl:

$M_{NaCl} = 58.44g/mol$
$n = \frac{m}{M}$
$n_{NaCl} = \frac{120g}{58.44g/mol}$
$n_{NaCl} = 2.053mol$

Using the ratio, since 1 mole of sodium carbonate is required to produce 2 moles of sodium chloride, cross-multiply the ratios:

$1:2 = x:2.053mol$
$2x = 2.053mol$
$x = 1.027mol$

Therefore 1.027 moles of sodium carbonate is required to produce the required amount of sodium chloride. Convert to mass for your final answer:

$n_{Na_2CO_3} = 1.027mol$
$M_{Na_2CO_3} = 105.99g/mol$
$m = nM$
$m = (1.027mol)(105.99g/mol)$
$m_{Na_2CO_3} = 108.85g$

Hope this helps :)

6 0

2 years ago