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inessss [21]
3 years ago
8

How many moles of solute are contained in a 500.0 milliliter solution that has a concentration of 0.35 M?

Chemistry
2 answers:
RUDIKE [14]3 years ago
8 0
I think the answer you are looking for is .18 moles
zepelin [54]3 years ago
7 0
Definitely B. 0.35 M/L * 1/2L = .0175 moles which rounds up to .18 moles
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Answer :

  • Carbonyl group : It is a functional group composed of a carbon atom that double bonded to oxygen atom. It is represented as C=O

Carboxylic group : It is the class of organic compound in which the carboxylic (-COOH) group is attached to a hydrocarbon is known as carboxylic.

The general formula of carboxylic is, C_nH_{2n+1}COOH. According to the IUPAC naming, the carboxylic are named as alkanoic acids.

Aldehyde group : It is the class of organic compound in which the (-CHO) group is attached to a hydrocarbon is known as aldehyde.

The general representation of aldehyde is, R-CHO. According to the IUPAC naming, the aldehyde are named as alkanals.

Ketone group : It is the class of organic compound in which the (-CO) group is directly attached to the two alkyl group of carbon is known as ketone.

The general representation of ketone is, R-CO-R^'. According to the IUPAC naming, the ketone are named as alkanone.

Ester group : It is the class of organic compound in which the (-COO) group is directly attached to the two alkyl group of carbon is known as ester.

The general representation of ester is, R-COO-R^'. According to the IUPAC naming, the ester are named as alkyl alkanoate.

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When dipentyl ether is treated with HI, what type of reaction occurs? both SN1 and SN2 SN2 E1 SN1 E2
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Answer:

SN2

Explanation:

The first step of ether cleavage is the protonation of the ether since ROH is a better leaving group than RO-.

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Dipentyl ether is a primary ether hence when treated with HI, the reaction with HI proceeds by SN2 mechanism as explained above.

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