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Maksim231197 [3]
2 years ago
11

A balloon starts out with a volume of 1.3 l at 115.3 kpa. if the temperature is held constant, what would the new volume be if t

he pressure inside the balloon was reduced to 58 kpa?
show all work and include units for each number. use sig fig rounding on your answer.
Chemistry
1 answer:
Anna35 [415]2 years ago
8 0

The new volume be if the pressure inside the balloon was reduced to 58kpa is 2.58 L.

<h3>What is ideal gas equation?</h3>

Ideal gas equation PV=nRT gives idea about the behavior of gases at different conditions and for this question the equation becomes:

P₁V₁ = P₂V₂, where

P₁ = initial pressure = 115.3 kpa

V₁ = initial volume = 1.3 L

P₂ = final pressure = 58 kpa

V₂ = final volume = ?

On putting all these values in the above equation, we get

V₂ = (115.3)(1.3) / (58) = 2.58 L

Hence resultant volume of gas is 2.58 L.

To know more about ideal gas equation, visit the below link:

brainly.com/question/18909295

#SPJ1

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Answer:

Mass = 279.23 g

Explanation:

Given data:

Number of moles of Fe₂O₃ = 3 mol

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Maximum amount of iron produced by reaction = ?

Solution:

Chemical equation:

Fe₂O₃ + 2Al    →     Al₂O₃  +  2Fe

Now we will compare the moles of iron with Al and iron oxide.

                          Fe₂O₃     :       Fe

                             1           :        2

                             3          :       2×3 = 6 mol

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                              2         :           2

                               5        :           5 mol

The number of moles of iron produced by Al are less so Al is limiting reacting and it will limit the amount of iron so maximum number of iron produced are 5 moles.

Mass of iron:

Mass = number of moles × molar mass

Mass =   5 mol  ×  55.845 g/mol

Mass = 279.23 g

 

3 0
2 years ago
How many moles are in 4.24kg of Na2CO3?
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