Answer:
Less than
Explanation:
The process of dissolution occurs as a kind of "tug of war". On one side are the solute-solute and solvent-solvent interaction forces, while on the other side are the solute-solvent forces.
Only when the solute-solvent forces are strong enough to overcome the pre-mixing forces do they overcome the "tug of war", and thus dissolution occurs.
Thus, it is concluded that the interaction forces between solute particles and solvent particles before they are combined are less than the interaction forces after dissolution.
Explanation:
The given reaction equation will be as follows.
![[FeSCN^{2+}] \rightleftharpoons [Fe^{3+}] + [SCN^{-}]](https://tex.z-dn.net/?f=%5BFeSCN%5E%7B2%2B%7D%5D%20%5Crightleftharpoons%20%5BFe%5E%7B3%2B%7D%5D%20%2B%20%5BSCN%5E%7B-%7D%5D)
Let is assume that at equilibrium the concentrations of given species are as follows.
![[Fe^{3+}] = 8.17 \times 10^{-3}](https://tex.z-dn.net/?f=%5BFe%5E%7B3%2B%7D%5D%20%3D%208.17%20%5Ctimes%2010%5E%7B-3%7D)
M
![[SCN^{-}] = 8.60 \times 10^{-3}](https://tex.z-dn.net/?f=%5BSCN%5E%7B-%7D%5D%20%3D%208.60%20%5Ctimes%2010%5E%7B-3%7D)
M
![[FeSCN^{2+}] = 6.25 \times 10^{-2}](https://tex.z-dn.net/?f=%5BFeSCN%5E%7B2%2B%7D%5D%20%3D%206.25%20%5Ctimes%2010%5E%7B-2%7D)
M
Now, first calculate the value of 
as follows.
![K_{eq} = \frac{[Fe^{3+}][SCN^{-}]}{[FeSCN^{2+}]}](https://tex.z-dn.net/?f=K_%7Beq%7D%20%3D%20%5Cfrac%7B%5BFe%5E%7B3%2B%7D%5D%5BSCN%5E%7B-%7D%5D%7D%7B%5BFeSCN%5E%7B2%2B%7D%5D%7D)
= 
= 
Now, according to the concentration values at the re-established equilibrium the value for ![[FeSCN^{2+}]](https://tex.z-dn.net/?f=%5BFeSCN%5E%7B2%2B%7D%5D)
will be calculated as follows.
![11.24 \times 10^{-4} = \frac{8.12 \times 10^{-3} \times 7.84 \times 10^{-3}}{[FeSCN^{2+}]}](https://tex.z-dn.net/?f=11.24%20%5Ctimes%2010%5E%7B-4%7D%20%3D%20%5Cfrac%7B8.12%20%5Ctimes%2010%5E%7B-3%7D%20%5Ctimes%207.84%20%5Ctimes%2010%5E%7B-3%7D%7D%7B%5BFeSCN%5E%7B2%2B%7D%5D%7D)
![[FeSCN^{2+}] = 5.66 \times 10^{-2}](https://tex.z-dn.net/?f=%5BFeSCN%5E%7B2%2B%7D%5D%20%3D%205.66%20%5Ctimes%2010%5E%7B-2%7D)
M
Thus, we can conclude that the concentration of in the new equilibrium mixture is 
M.
Answer:
explain what need to be done here pls? what do you need?
Explanation:
It has mass and takes up space is correct.
H. using a pulley system can reduce the load force, over a greater distance.<span />
