All categories

3 years ago

Anyone know the answer to this one?

Chemistry

1 answer:

sergey [27]3 years ago

5 0

Answer:

C) 0.24 M

Explanation:

The given chemical reaction is presented as follows;

H₂SO₄(aq) + 2 KOH(aq) → K₂SO₄(aq) + 2 H₂O(l)

The titration experiment results are;

Volume of H₂SO₄(aq) used = 12.0 mL

Volume of KOH (aq) used = 36.0 mL

Concentration of KOH (aq) = 0.16 M

The number of moles of KOH present, n = 0.16 M × 36/1000 = 0.00576 moles

From the given reaction, 1 mole of H₂SO₄ reacts with 2 moles of KOH to give 1 mole of K₂SO₄ and 2 moles of H₂O

Therefore, 0.00576 moles of KOH reacts with (1/2) × 0.00576 moles = 0.00288 moles of H₂SO₄

Therefore, for the reaction;

The number of moles of H₂SO₄ in 12.0 mL of H₂SO₄ = 0.00288 moles

The concentration of the H₂SO₄ = 0.00288 M/(12.0 mL) = 0.24 M

The concentration of H₂SO₄ in the reaction = 0.24 M.

You might be interested in

If you only wanted to increase the particle motion of a gas without increasing any of its other properties, which would the most

andrey2020 [161]

Answer:

Explanation:

5 0

2 years ago

How many neutrons are in the element sulfur-34

igomit [66]

Answer:

8 neutrons

Explanation:

6 0

3 years ago

Read 2 more answers

Automobile airbags contain solid sodium azide, NaN3, that reacts to produce nitrogen gas when heated, thus inflating the bag. 2N

Vitek1552 [10]

Answer : The value of work done for the system is 1144.69 J

Explanation :

First we have to calculate the moles of $NaN_3$

$\text{Moles of }NaN_3=\frac{\text{Mass of }NaN_3}{\text{Molar mass of }NaN_3}$

Molar mass of $NaN_3$ = 65.01 g/mole

$\text{Moles of }NaN_3=\frac{20.2g}{65.01g/mole}=0.311mole$

Now we have to calculate the moles of nitrogen gas.

The balanced chemical reaction is,

$2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)$

From the balanced reaction we conclude that

As, 2 mole of $NaN_3$ react to give 3 mole of $N_2$

So, 0.311 moles of $NaN_3$ react to give $\frac{0.311}{2}\times 3=0.466$ moles of $N_2$

Now we have to calculate the volume of nitrogen gas.

Using ideal gas equation:

$PV=nRT$

where,

P = Pressure of $N_2$ gas = 1.00 atm

V = Volume of $N_2$ gas = ?

n = number of moles $N_2$ = 0.466 mole

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of $N_2$ gas = $22^oC=273+22=295K$

Putting values in above equation, we get:

$1.00atm\times V=0.466mole\times (0.0821L.atm/mol.K)\times 295K$

$V=11.3L$

As initially no nitrogen was present. So,

Volume expanded = Volume of nitrogen evolved

Thus,

Expansion work = Pressure × Volume

Expansion work = 1.00 atm × 11.3 L

Expansion work = 11.3 L.atm

Conversion used : (1 L.atm = 101.3 J)

Expansion work = 11.3 × 101.3 = 1144.69 J

Therefore, the value of work done for the system is 1144.69 J

5 0

3 years ago

How to convert 151cm to km

maw [93]

Just multiply 151 x 0.0001

That will equal:

0.00151 km or if you want to round it then it would be 0.02km

5 0

3 years ago

Read 2 more answers

With the exception of our sun, most stars are huge, bright balls of gas located trillions of miles away from earth true or false

Ivenika [448]

Answer:

True

Explanation:

Stars are bright and enormous astronomical bodies that are located at a large distance from the earth. They are made up of the lightest gaseous elements namely hydrogen and helium. These hydrogen atoms undergo the reaction of nuclear fusion, which fuels the energy of the star and allows the star to shine, releasing a large amount of energy. They are located about trillions of miles away from the location of the earth, due to which they appear smaller in size.

Thus, the above-given statement is True.

3 0

3 years ago

Read 2 more answers