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Natali5045456 [20]
2 years ago
6

According to Newton's second law of motion, a larger force acting on an object causes a greater(................................

..) of that object
Chemistry
2 answers:
galina1969 [7]2 years ago
5 0

Answer:

acceleration

learnt this in 8th grade

taurus [48]2 years ago
5 0

acceleration

Newton's second law : F = m.a

F proportional to m and a

F > than a >

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I WILL GIVE U BRAINLIEST
PtichkaEL [24]

Answer:

guidelines

Explanation:

It gives perameters for her abilities :)

7 0
2 years ago
Read 2 more answers
Does a laboratory balance measure mass or weight
kolezko [41]
A balance in a lab measures the weight of a substance or object.
Weight is the mass of the body x the gravitation pull on the mass of the object.

So the mass of the object can be found by dividing the weight by gravitational constant.

The gravitational constant on earth is 1. so if a balance says that a substance weighs 300g then its mass is also 300g on earth because 300/1 = 300.

Hope that helps :)
5 0
3 years ago
0.7 L of H2 enters a reaction at standard temperature and pressure.
ASHA 777 [7]

Answer:

1.88 × 10²³ particles

Explanation:

Given data:

Volume of H₂ = 0.7 L

Number of particles at STP = ?

Solution:

First of all we will calculate the number of moles of H₂.

PV = nRT

n = PV / RT

n = 1 atm . 7 L / 0.0821 L. atm. mol⁻¹. k⁻¹ × 273.15 K

n = 7 atm. L / 22.43 L. atm. mol⁻¹

n = 0.312 mol

it is known that,

2 g H₂ = 1 mol = 6.022 × 10²³ particles

For 0.312 mol

              0.312 × 6.022 × 10²³ particles

                    1.88 × 10²³ particles

6 0
3 years ago
2. Na2SiO3(s) + HF(aq) !H2SiF6(aq) + NaF(aq) + H2O (l)
Alex

Answer:

a) Na2SiO3(s) + 8HF(aq) → H2SiF6(aq) + 2NaF(aq) + 3H2O (l)

b) <u>2.40 moles HF</u>

c) <u>5.25 grams NaF</u>

<u>d)0.609 grams Na2SiO3</u>

<u>e) </u> <u>0.89 grams Na2SiO3</u>

Explanation:

Step 1: Data given

Step 2: The balanced equation

Na2SiO3(s) + 8HF(aq) → H2SiF6(aq) + 2NaF(aq) + 3H2O (l)

b) How many moles of HF are needed to react with 0.300 mol of Na2SiO3?

For 1 mol Na2SiO3 we need 8 moles HF to produce 1 mol H2SiF6, 2 moles NaF and 3 moles H2O

For 0.300 moles Na2SiO3 we'll need 8*0.300 = <u>2.40 moles HF</u>

<u />

c. How many grams of NaF form when 0.500 mol of HF reacts with excess Na2SiO3?

For 1 mol Na2SiO3 we need 8 moles HF to produce 1 mol H2SiF6, 2 moles NaF and 3 moles H2O

For 0.500 moles we'll have 0.500 / 4 = 0.125 moles NaF

Mass NaF = 0.125 moles * 41.99 g/mol

Mass NaF = <u>5.25 grams NaF</u>

<u />

d. How many grams of Na2SiO3 can react with 0.800 g of HF?

Moles HF = 0.800 grams / 20.01 g/mol

Moles HF = 0.0399 moles

For 1 mol Na2SiO3 we need 8 moles HF to produce 1 mol H2SiF6, 2 moles NaF and 3 moles H2O

For 8 moles we need 1 moles Na2SiO3 to react

For 0.0399 moles we need 0.0399/8 = 0.00499 moles Na2SiO3

Mass Na2SiO3 = 0.00499 moles * 122.06 g/mol  

Mass Na2SiO3 = <u>0.609 grams Na2SiO3</u>

Using your answer to part d-If you started with 1.5 g of Na2SiO3how many grams would be left after the reaction is complete?

Number of moles HF = 0.0399 moles

Number of moles Na2SiO3 = 1.5 grams / 122.06 g/mol = 0.0123 moles

For 1 mol Na2SiO3 we need 8 moles HF to produce 1 mol H2SiF6, 2 moles NaF and 3 moles H2O

For 8 moles we need 1 moles Na2SiO3 to react

For 0.0399 moles we need 0.0399/8 = 0.00499 moles Na2SiO3

There will remain 0.0123 - 0.00499 = 0.00731 moles  Na2SiO3

Mass Na2SiO3 remaining = 0.00731 * 122.06 g/mol = <u>0.89 grams Na2SiO3</u>

<u />

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7 0
3 years ago
What is the concentration of a solution prepared by dissolving 100g of sorbitol in 1000 ml of water?
disa [49]

first you divide them together and get an answer of 10 then you times it by 5 and your answer is   50 ml


7 0
3 years ago
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