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just olya [345]

3 years ago

14

Attempt 4 A galvanic cell has an X electrode with X 2 plus ions in the left beaker and a Y electrode with Y 2 plus ions in the r

ight beaker. A salt bridge connects the two halves.A galvanic (voltaic) cell has the generic metals X and Y as electrodes. X is more reactive than Y, that is, X more readily reacts to form a cation than Y does. Classify the descriptions by whether they apply to the X or Y electrode.

1 answer:

babymother [125]3 years ago

4 0

Answer:

See explaination

Explanation:

Since X is more reactive than Y

=> X is oxidized to X2+ and Y2+ is reduced to Y

Overall cell reaction is:

X(s) + Y2+(aq) => X2+(aq) + Y(s)

please kindly see attachment for further solution.

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A block of material has a volume of 50 cubic centimeters, and a mass of 1,000 grams; what is that object's density?

zhannawk [14.2K]

Answer:

Density = $20\ g/cm^3$

Explanation:

Given that,

Mass of the object, m = 1000 g

Volume of the block, V = 50 cm³

We need to find the density of the object. Density is equal to mass per unit volume.

d = m/V

$d=\dfrac{1000\ g}{50\ cm^3}\\\\=20\ g/cm^3$

So, the density of the object is $20\ g/cm^3$ .

8 0

3 years ago

The combustion of liquid methanol has a change in enthalpy of -1278 kJ. How much energy will you get from burning 245.0 g of met

Nookie1986 [14]

Answer : 9773 kJ

Explanation:

Exothermic reactions are defined as the reactions in which energy of the product is lesser than the energy of the reactants. The total energy is released in the form of heat and $\Delta H$ for the reaction comes out to be negative.

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of methanol}=\frac{245.0g}{32.04/mol}=7.647moles$

Given : Change in enthalpy on combustion of 1 mole of methanol = -1278 kJ

According to stoichiometry :

1 mole of methanol produce energy = 1278 kJ

Thus 7.647 moles of methanol produce energy = $\frac{1278}{1}\times 7.647=9773kJ$

Thus 9773 kJ of energy is produced from burning 245.0 g of methanol in excess oxygen

3 0

3 years ago

Which statement gives a disadvantage of multicellular organisms?

dexar [7]

Answer: B. They reproduce slower than unicellular organisms

Explanation:

In unicellular organisms there is a single cell which performs all the functions like digestion, respiration, and reproduction. The cell reproduce by cell division. The single parent cell divides into two identical daughter cells. But multicellular organisms exhibit multiple cells and their reproduction is complex. They reproduce by sexual mode of reproduction in which separate sex cells are produced when they fuse form zygote which is the precursor of new organism. This process is slower than that of the cell division and production of progeny by the unicellular organisms. Thus reproduction is slower in multicellular organism this is the disadvantage in multicellular organisms.

6 0

3 years ago

Read 2 more answers

You mix 200. mL of 0.400M HCl with 200. mL of 0.400M NaOH in a coffee cup calorimeter. The temperature of the solution goes from

GuDViN [60]

Answer : The enthalpy of neutralization is, 56.012 kJ/mole

Explanation :

First we have to calculate the moles of HCl and NaOH.

$\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=0.400mole/L\times 0.200L=0.08mol$

$\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=0.400mole/L\times 0.200L=0.08mol$

The balanced chemical reaction will be,

$HCl+NaOH\rightarrow NaCl+H_2O$

From the balanced reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of NaOH

So, 0.08 mole of HCl neutralizes by 0.08 mole of NaOH

Thus, the number of neutralized moles = 0.08 mole

Now we have to calculate the mass of water.

As we know that the density of water is 1 g/ml. So, the mass of water will be:

The volume of water = $200mL+200L=400mL$

$\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/ml\times 400mL=400g$

Now we have to calculate the heat absorbed during the reaction.

$q=m\times c\times (T_{final}-T_{initial})$

where,

q = heat absorbed = ?

$c$ = specific heat of water = $4.18J/g^oC$

m = mass of water = 400 g

$T_{final}$ = final temperature of water = $27.78^oC=273+25.10=300.78K$

$T_{initial}$ = initial temperature of metal = $25.10^oC=273+27.78=298.1K$

Now put all the given values in the above formula, we get:

$q=400g\times 4.18J/g^oC\times (300.78-298.1)K$

$q=4480.96J$

Thus, the heat released during the neutralization = -4480.96 J

Now we have to calculate the enthalpy of neutralization.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy of neutralization = ?

q = heat released = -4480.96 J

n = number of moles used in neutralization = 0.08 mole

$\Delta H=\frac{-4480.96J}{0.08mole}=-56012J/mole=-56.012kJ/mol$

The negative sign indicate the heat released during the reaction.

Therefore, the enthalpy of neutralization is, 56.012 kJ/mole

8 0

3 years ago

How do u get the formulae for sodium oxide

Maslowich

Answer:

The Chemical formula of sodium is Na.

The Chemical formula of oxide is O.

Explanation:

Therefore we know that the term 'valency' is called as the combining capacity of an atom of an element.

So by taking the valency of Sodium and Oxide, we get

Sodium with valency '1' and Oxide with valency '2'.

Na O

1 2

When you cross over you get 'Na2O' as the formula for sodium oxide.

Hope this is helpful for you!

Don't forget to rate or give brainliest answer.!!

TY.

5 0

3 years ago

Read 2 more answers