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just olya [345]
3 years ago
14

Attempt 4 A galvanic cell has an X electrode with X 2 plus ions in the left beaker and a Y electrode with Y 2 plus ions in the r

ight beaker. A salt bridge connects the two halves.A galvanic (voltaic) cell has the generic metals X and Y as electrodes. X is more reactive than Y, that is, X more readily reacts to form a cation than Y does. Classify the descriptions by whether they apply to the X or Y electrode.

Chemistry
1 answer:
babymother [125]3 years ago
4 0

Answer:

See explaination

Explanation:

Since X is more reactive than Y

=> X is oxidized to X2+ and Y2+ is reduced to Y

Overall cell reaction is:

X(s) + Y2+(aq) => X2+(aq) + Y(s)

please kindly see attachment for further solution.

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Gravity

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3 years ago
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When two or more substances combine, but each keeps its own properties, what is the new combination called A) Element B) Mixture
vodka [1.7K]
Hi.
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3 years ago
The kinetic energy of a 10.3 g golf ball traveling at 48.0 m/s is
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To work out the kinetic energy of an object, you use the formula:


E = 0.5 x (mass) x (velocity)^2


One important thing, though. The units MUST be consistent. Mass needs to be in kilograms, and velocity in metres per second.


To convert the mass form grams to kilograms, we need to divide it by 1000, getting 0.0103 kg. Since the velocity is already in the units we need, we can just plug the numbers into the equation to get:


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3 0
3 years ago
A 150.0 mL sample of an aqueous solution at 25°C contains 15.2 mg of an unknown nonelectrolyte compound. If the solution has an
inysia [295]

<u>Answer:</u> The molar mass of the unknown compound is 223.2 g/mol

<u>Explanation:</u>

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

\pi=iMRT

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\pi = osmotic pressure of the solution = 8.44 torr

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R = Gas constant = 62.3637\text{ L torr }mol^{-1}K^{-1}

T = temperature of the solution = 25^oC=[273+25]=298K

Putting values in above equation, we get:

8.44torr=1\times M\times 62.3637\text{ L. torr }mol^{-1}K^{-1}\times 298K\\\\M=\frac{8.44}{1\times 62.3637\times 298}=4.54\times 10^{-4}M

To calculate the molecular mass of solute, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Molarity of solution = 4.54\times 10^{-4}M

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Volume of solution = 150.0 mL

Putting values in above equation, we get:

4.54\times 10^{-4}M=\frac{0.0152\times 1000}{\text{Molar mass of unknown compound}\times 150.0}\\\\\text{Molar mass of unknown compound}=\frac{0.0152\times 1000}{150.0\times 4.54\times 10^{-4}}=223.2g/mol

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allochka39001 [22]
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