Answer:
the square root of the tension divided by the linear density (mass per length)
Answer:
23.67 m
Explanation:
We are given;
Frequency; f = 0.3 Hz
Speed; v = 7.1 m/s
Now, formula to get the wavelength is from the wave equation which is;
v = fλ
Where λ is wavelength
Making λ the subject, we have;
λ = v/f
λ = 7.1/0.3
λ = 23.67 m
Answer:
The ball will have an upward velocity of 6 m/s at a height of 5.51 m.
Explanation:
Hi there!
The equations of height and velocity of the ball are the following:
y = y0 + v0 · t + 1/2 · g · t²
v = v0 + g · t
Where:
y = height at time t.
y0 = initial height.
v0 = initial velocity.
t = time.
g = acceleration due to gravity (-9.81 m/s² considering the upward direction as positive).
v = velocity of the ball at time t.
Placing the origin at the throwing point, y0 = 0.
Let´s use the equation of velocity to obtain the time at which the velocity is 12.0 m/s / 2 = 6.00 m/s.
v = v0 + g · t
6.00 m/s = 12.0 m/s -9.81 m/s² · t
(6.00 - 12.0)m/s / -9.81 m/s² = t
t = 0.612 s
Now, let´s calculate the height of the baseball at that time:
y = y0 + v0 · t + 1/2 · g · t² (y0 = 0)
y = 12.0 m/s · 0.612 s - 1/2 · 9.81 m/s² · (0.612 s)²
y = 5.51 m
The ball will have an upward velocity of 6 m/s at a height of 5.51 m.
Have a nice day!
Three physical characteristics of a crushed can would be
smooth,shiny,sharp
Answer:
See Below.
Explanation:
I can't transpose the diagram onto Brainly. I'll do my best to describe what is going on.
- Draw a horizontal line one inch from the each border of the page.
- To show what each of A and B are supporting, use an up arrow.
- Label the Ends A and B. B is on the right side.
- Put the physics teacher about 1.5 inches from B. His force goes down.
- Label it as 75 * 9.8 Newtons
- Put the platform mass about 2.5 inches from B
- Label it as 10 * 9.8 Newtons
- B is the balance point
- Now put in the distances. The lines are horizontal
- Student A: 10 meters
- Center of mass: 4 meters to B
- Mass of Physics: 2 meters.
Now you are ready to develop the equation
Clockwise
There is only 1 force where B is the Balance point that is going clockwise
10 * Force A
The AntiClockwise Moments
Platform: 4*10kg * 9.8 = 392 N m
Physics T: 2 * 75 * 9.8 = 1470 N m
So the Anti Clockwise moments = the clockwise moments.
10 * Force A = 392 NM + 1470NM Divide by 10. Remember that is in meters
Force A = 1862 N M / 10 10 M = 186 N
Does that make some sort of sense? It should Student A is the furthest distance from where all the action is at B. Therefore he is carrying the lightest weight.
Now what is the total force?
(75 + 10 ) * 9.8 = 85 * 9.8 = 833
This is one of those strange things that won't make sense until it does. Read the next sentence carefully. B is carrying most of the weight. Remember Newtons measure weight.
Support of A = 186 N
Support of B = x
Total of A+B = 933
186 + x = 833
x = 933 - 186
x = 647
So the forces are
A supports 186
B supports 647