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2 years ago

When Simon grows (let’s say he doubles his mass) what happens to his GPE when he is at the balcony?

Physics

1 answer:

DerKrebs [107]2 years ago

5 0

Answer:

His gravitational potential energy will increase as well.

Explanation:

Let gpe represent gravitational potential energy.

gpe = mass × gravitational field strength × height

From the formula above, we can conclude that as the mass of a body increases, it's gpe increases too.

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Suppose a woman raises a 65 N object in 2m in 4 seconds.

Novosadov [1.4K]

Answer:

$\huge\boxed{\sf P.E = 130\ Joules}$

$\huge\boxed{\sf P = 32.5\ Watts}$

Explanation:

<u>Given Data:</u>

Weight = W = 65 N

Height = h = 2 m

Time = t = 4 secs

<u>Required:</u>

Power = P = ?

Work Done in the form of Potential Energy = P.E. = ?

<u>Formula:</u>

P.E. = Wh

P = P.E. / t

<u>Solution:</u>

P.E. = (65)(2)

P.E = 130 Joules

P = P.E. / t

P = 130 / 4

P = 32.5 Watts

$\rule[225]{225}{2}$

Hope this helped!

8 0

3 years ago

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Ede4ka [16]

I’m not sure if this will help but I found: https://prezi.com/l0fa6du3b9kp/going-off-the-grid-assignment/?fallback=1 and

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3 years ago

Where does the kinetic energy come fromwhen you roll down a hill?

Lapatulllka [165]

From the change of GPE into KE. Conservation of energy tells us this.

8 0

4 years ago

Protein synthesis is vital for cell growth and metabolism. Transcription and translation are known as the central dogma of biolo

Liono4ka [1.6K]

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3 years ago

Read 2 more answers

Suppose that the acceleration of a model rocket is proportional to the difference between 160 ft/sec and the rocket's velocity.

Levart [38]

Answer:

Explanation:

Given ,

dv / dt = k ( 160 - v )

dv / ( 160 - v ) = kdt

ln ( 160 - v ) = kt + c , where c is a constant

when t = 0 , v = 0

Putting the values , we have

c = ln 160

ln ( 160 - v ) = kt + ln 160

ln ( 160 - v / 160 ) = kt

(160 - v ) / 160 = $e^{kt}$

1 - v / 160 = $e^{kt }$

v / 160 = 1 - $e^{kt }$

v = 160 ( 1 - $e^{kt }$ )

differentiating ,

dv / dt = - 160k $e^{kt }$

acceleration a = - 160k $e^{kt }$

given when t = 0 , a = 280

280 = - 160 k

k = - 175

a = - 160 x - 175 $e^{kt}$

a = 28000 $e^{kt}$

when a = 128 t = ?

128 = 28000 $e^{kt}$

$e^{kt }$ = .00457

5 0

3 years ago