Answer: a = 1.32m/s2
Therefore, the average acceleration is 1.32m/s2
Explanation:
Acceleration is the rate of change in the velocity per time
a = change in velocity/time
a = ∆v/t
average acceleration a = (v2 -v1)/t. ....1
Given;
Final velocity v2 = 1.63m/s
Initial velocity v1 = -1.15ms
time taken t = 2.11s
Substituting into eqn 1
a = [1.63 - (-1.15)]/2.11
a = (1.63+1.15)/2.11
a = 2.78/2.11
a = 1.32m/s2
Therefore, the average acceleration is 1.32m/s2
We have: F = m×a
Here, m = 90 Kg
a = 15 m/s²
Substitute their values into the expression:
F = 90 × 15
F = 1350 N
In short, Your Answer would be Option D
Hope this helps!
Answer:
the answer is slows and greater
Hopes it helps!
Answer:
A)
B)
C)
Explanation:
Given that a pendulum is suspended by a shaft with a very light thin rod.
Followed by the given information: m = 100 g, I = 0.5 m, g = 9.8 m / s²
We can determine the answer to these questions using angular kinematics.
Angular kinematics is just derived from linear kinematics but in different symbols, and expressions.
Here are the formulas for angular kinematics:
- θ = ωt
- ∆w =
- L [Angular momentum] = mvr [mass × velocity × radius]
A) What is the minimum speed required for the pendulum to traverse the complete circle?
We can use the formula v = √gL derived from
B) The same question if the pendulum is suspended with a wire?
C) What is the ratio of the two calculated speeds?
