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nataly862011 [7]
3 years ago
11

A clam of mass 0.12 kg dropped by a seagull takes 3.0 s to hit the ground. [Neglect friction.]

Physics
1 answer:
jarptica [38.1K]3 years ago
6 0

-- The acceleration of gravity is 9.8 m/s².
So if there's no air resistance, the speed of a falling object
always increases by 9.8 m/s for every second it falls.

             Speed  =  (original speed) + (gravity  x  falling time)

-- If it has no vertical speed when it started, then at the end
of 3 seconds, its speed is

                         =       (0)            + (9.8 m/s²  x  3 sec)

                       Velocity  =  29.4 m/s downward . 
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A car traveling at 14 m/s accelerates at 3.5 m/s² for 5 seconds. How much distance does it travel during that time?​
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Answer: 113.75

Explanation:

You know

acceleration = a = 3.5 m/s²

time = t = 5 seconds

initial velocity = u = 14 m/s

Unknown is distance = s = ?

Use equation: s = ut + \frac{1}{2} at²

Substitute all the known values inside the equation:

s = (14*5) + 0.5 * 3.5 * 5²

s = 70 + 43.75 = 113.75 m

The car travels 113.75 metres.

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If a 42kg rolling object slows from 11.5m/s to 3.33m/s how much work did friction do
geniusboy [140]

Answer: 1608.39 J

Explanation: Given that the

mass M = 42kg

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V = 3.33m/s

how much work did friction do

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Work done = Ma × distance

But acceleration a = V/t

Work done = M × V/t × d

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Where d/t = velocity

Therefore,

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8 0
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an eagle has a mass of 8 kg and is flying 85 m above he ground with a speed of 20 m/s. what is the total mechanical energy of th
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85+5=90 :DD
90-20=70 :DDD

Good lessons.
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