Ask question

Ask question

All categories

nataly862011 [7]

2 years ago

11

A clam of mass 0.12 kg dropped by a seagull takes 3.0 s to hit the ground. [Neglect friction.]

1 answer:

jarptica [38.1K]2 years ago

6 0

-- The acceleration of gravity is 9.8 m/s².
So if there's no air resistance, the speed of a falling object
always increases by 9.8 m/s for every second it falls.

   Speed = (original speed) + (gravity x falling time)

-- If it has no vertical speed when it started, then at the end
of 3 seconds, its speed is

   = (0)    + (9.8 m/s² x 3 sec)

   Velocity = 29.4 m/s downward .

You might be interested in

What is the moon phase today

Elis [28]

Waxxing Gibbous Phase

4 0

2 years ago

Read 2 more answers

The three types of seismic waves are P waves, S waves and T waves. Please select the best answer from the choices provided T F

ikadub [295]

The correct answer is False

7 0

2 years ago

Read 2 more answers

The motion of a car on a position-time graph is represented with a horizontal line. What does this indicate about the car's moti

Ksenya-84 [330]

Answer: The answer is B

Explanation: It is staying in a steady speed position

5 0

2 years ago

Read 2 more answers

Two balls of clay, with masses M1 = 0.49 kg and M2 = 0.47 kg, are thrown at each other and stick when they collide. Mass 1 has a

malfutka [58]

Answer:

a) $p_i=1.568\hat{i}+0.752 \hat{j}$

b) $v_{fx}=1.668\ m.s^{-1}$

c) $v_{fy}=0.7999\ m.s^{-1}$

Explanation:

Given masses:

$m_1=0.49\ kg$

$m_2=0.47\ kg$

Velocity of mass 1, $v_1=3.2 \hat{i}\ m.s^{-1}$

Velocity of mass 2, $v_2=1.6 \hat{j}\ m.s^{-1}$

a)

Initial momentum:

$p_i=m_1.v_1+m_2.v_2$

$p_i=0.49\times 3.2 \hat{i}+0.47\times 1.6 \hat{j}$

$p_i=1.568\hat{i}+0.752 \hat{j}$

b)

magnitude of initial momentum:

$p_i=\sqrt{1.568^2+0.752 ^2}$

$p_i=1.739\ kg.m.s^{-1}$

From the conservation of momentum:

$p_f=p_i$

$m_f.v_f=1.739$

$v_f=\frac{1.739}{0.49+0.47}$

$v_f=1.85\ m.s^{-1}$ is the magnitude of final velocity.

Direction of final velocity will be in the direction of momentum:

$tan\theta=\frac{0.752 }{1.568}$

$\theta=25.62^{\circ}$

$\therefore v_{fx}=1.85\ cos25.62^{\circ}$

$v_{fx}=1.668\ m.s^{-1}$

c)

Vertical component of final velocity:

$v_{fy}=1.85\ sin 25.62^{\circ}$

$v_{fy}=0.7999\ m.s^{-1}$

6 0

3 years ago

Are all these a chemical change <br> Burn <br> Dissolve<br> Rust<br> Explode

zloy xaker [14]

Rust is not because it does not occur through a chemical process

6 0

2 years ago