Answer:
Let the momentum of the orange train be positive
P = 100 * 8 - 200 * 1 = 600 kg-m/s
P(final) = 600 kg-m/s
P / M = 600 kg-m/sec / 300 kg = 2 m/s
Answer-B final momentum = 600 kg-m/s
Answer:
1 Ba + 1 SO4^-2 -----> 1 Ba^2 SO4^-2
Explanation:
Answer:
0.011 N-m
Explanation:
Given that
The mass of a solid cylinder, m = 30 kg
The radius of the cylinder, r = 0.18 m
The acceleration of the cylinder, 
It rotates about an axis through its center. We need to find the torque acting on the cylinder. The formula for the torque is given by :
Where
I is the moment of inertia of the cylinder,
For cylinder,
So,
So, the required torque on the cylinder is 0.011 N-m.
Use: dsin(θ) = mλ where d is slit separation, m is fringe order (1 here), and
θ = 0.183
Now λ = dsin(θ) /m = (0.215e-3)(sin(0.183))/1 = 6.867e-7 or λ = 687.7nm
(red laser)
Answer:
4 s
Explanation:
u = 19.6 m/s, g = 9.8 m /s^2
Let the time taken to reach the maximum height is t.
Use first equation of motion.
v = u + at
At maximum height, final velocity v is zero.
0 = 19.6 - 9.8 x t
t = 19.6 / 9.8 = 2 s
As the air resistance be negligible, is time taken to reach the ground is also 2 sec.
So, total time taken be the ball to reach at original point = 2 + 2 = 4 s
