Question

What is the molar mass of a gas that fills a 1.20l container at a temperature of 305k. the gas has a mass of 1.98g and the container is at a pressure of 0.960 atm.

Answer 1

Answer:

The molar mass of the gas should be 43.0 g/mol.

Explanation:

1.Use the ideal gas law($PV=nRT$) & the formula for moles and molar mass($n=m/M$).

2.Insert the equation $n=m/M$ into $PV=nRT$ and re-arrange to solve for M(molar mass). $M = mRT/PV$

3.Insert values and use the gas constant R = $0.082 (L * atm)/(K * mol)$ since the volume is in liters and the pressure is in atmosphere units.

$M = mRT/PV = \frac{(1.98g)(0.082 L*atm/(K*mol))(305 K)}{(0.960 atm)(1.20 L)}$

4. Your answer should be 42.99 g/mol or 43.0 g/mol.

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