Answer:
The rotation of the Earth.
1 mole Hg ---------------- 6.02x10²³ atoms
?? ------------------------- 1.30 x10⁷ atoms
1.30x10⁷ x 1 / 6.02x10²³ =
= 1.30x10⁷ / 6.02x10²³ => 2.159x10⁻¹⁷ moles
hope this helps!
0.447 is the mole fraction of Nitrogen in this mixture.
mole fraction of nitrogen= moles of nitrogen/total moles
mole fraction of nitrogen=0.85/1.90
mole fraction of nitrogen=0.447
The product of the moles of a component and the total moles of the solution yields a mole fraction, which is a unit of concentration measurement. Because it is a ratio, mole fraction is a unitless statement. The sum of the components of the mole fraction of a solution is one. In a mixture of 1 mol benzene, 2 mol carbon tetrachloride, and 7 mol acetone, the mole fraction of the acetone is 0.7. This is computed by dividing the sum of the moles of acetone in the solution by the total number of moles of the solution's constituents:
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There is one missing point in the question.
The formula to find an increase in boiling Temperature is :
ΔT = kb x M
ΔT = is the increase in boiling Temperature
Kb = Boiling point constant of the Solvent
M = Molarity
You did not provide the Kb. If you have it, you just have to insert it to the formula to find the ΔT.
And assuming that the other solution is water, you just have to add it up with 100 Celcius
Answer:
The resulting solution contains approximately 666 g of water.
Explanation:
In the initial solution we have:
1g salt : 8g sugar : 200g water
This means that the ratios are:
![\frac{salt}{sugar} = \frac{1}{8} \\\\\frac{sugar}{water} = \frac{8}{200} =\frac{1}{25}](https://tex.z-dn.net/?f=%5Cfrac%7Bsalt%7D%7Bsugar%7D%20%20%3D%20%5Cfrac%7B1%7D%7B8%7D%20%5C%5C%5C%5C%5Cfrac%7Bsugar%7D%7Bwater%7D%20%3D%20%5Cfrac%7B8%7D%7B200%7D%20%3D%5Cfrac%7B1%7D%7B25%7D)
In the final solution we have:
5g salt: xg sugar: yg water
The new ratios are:
![\frac{salt}{sugar} = \frac{3}{8} \\\\\frac{sugar}{water} = \frac{1}{50}](https://tex.z-dn.net/?f=%5Cfrac%7Bsalt%7D%7Bsugar%7D%20%3D%20%5Cfrac%7B3%7D%7B8%7D%20%5C%5C%5C%5C%5Cfrac%7Bsugar%7D%7Bwater%7D%20%3D%20%5Cfrac%7B1%7D%7B50%7D)
Now we can calculate the amount of sugar in the final solution:
![\frac{salt}{sugar} = \frac{5}{x} =\frac{3}{8} \\\\X = 13.333 g](https://tex.z-dn.net/?f=%5Cfrac%7Bsalt%7D%7Bsugar%7D%20%20%3D%20%5Cfrac%7B5%7D%7Bx%7D%20%3D%5Cfrac%7B3%7D%7B8%7D%20%5C%5C%5C%5CX%20%3D%2013.333%20g)
Finally, we calculate the amount of water:
![\frac{sugar}{water} = \frac{13.333}{y} = \frac{1}{50} \\y = 666.667 g](https://tex.z-dn.net/?f=%5Cfrac%7Bsugar%7D%7Bwater%7D%20%3D%20%5Cfrac%7B13.333%7D%7By%7D%20%3D%20%5Cfrac%7B1%7D%7B50%7D%20%5C%5Cy%20%3D%20666.667%20g)