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faust18 [17]
3 years ago
8

What is the r.a.m. value of krypton (Kr)?

Chemistry
1 answer:
meriva3 years ago
3 0
36 amu I am pretty sure
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Compare the arrangements of individual particles in solids, liquids, and has
erastovalidia [21]
Solids have particles that stay in place and vibrate (least energy)
Liquids have enough energy to slide past each other and have no definite shape.
Gas has a lot of energy and moves freely with no certain shape or volume
5 0
3 years ago
When 3.0g of magnesium is burnt in 2.00g of oxygen, 5.00g of magnesium oxide is produced. What mass of magnesium oxide will be f
guajiro [1.7K]

Answer: -

8.00 g

The law of conservation of mass

Explanation: -

When magnesium burns in air it combines with oxygen to form magnesium oxide.

The mass of the product is the mass of the magnesium oxide.

The mass of the reactant is the mass of the magnesium + mass of the oxygen.

Since matter cannot be created or destroyed according to the law of conservation of mass,

Mass of Magnesium oxide formed = mass of magnesium reacted + mass of oxygen reacted

= 3.00 g + 5.00 g

= 8.00 g

3 0
3 years ago
Who tryna date? like ong
Elanso [62]

Answer:

Im confused. Do you need help with something?

Explanation:

4 0
3 years ago
Read 2 more answers
What volume in mL of 0.220 M HBr solution is required to produce 0.0130 moles of HBr?
yulyashka [42]

Answer: A volume of 59 mL of 0.220 M HBr solution is required to produce 0.0130 moles of HBr.

Explanation:

Given: Moles = 0.0130 mol

Molarity = 0.220 M

Molarity is the number of moles of solute present in liter of a solution.

Molarity = \frac{moles}{volume (in L)}

Substitute the values into above formula as follows.

Molarity = \frac{moles}{volume (in L)}\\0.220 M = \frac{0.0130 mol}{Volume (in L)}\\Volume (in L) = 0.059 L

As 1 L = 1000 mL

So, 0.059 L = 59 mL

Thus, we can conclude that a volume of 59 mL of 0.220 M HBr solution is required to produce 0.0130 moles of HBr.

8 0
3 years ago
EASY
eimsori [14]

Answer:

I'm too lazy to read that

Explanation:

lol

8 0
3 years ago
Read 2 more answers
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