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2 years ago

Calculate the mass in grams of NaCl required to prepare 0.500 L of a 0.500 M solution.

Chemistry

1 answer:

IceJOKER [234]2 years ago

7 0

Answer:

14.61 g NaCl

Explanation:

Molarity = moles / volume of solution (litres)

0.500 = moles / 0.500 L

moles = 0.25

Molar mass of NaCl is 58.44 g NaCl /1 mol NaCl.

0.25 moles NaCl x 58.44 g NaCl /1 mol NaCl

= 14.61 g NaCl

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A silicon wafer with dimensions 15.00 cm x 15.00 cm x 0.0400 cm

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The silicon wafer contains 20.96 g of silicon.

The mole of a substance is related to its mass and molar mass by the following equation:

<h3>Mole = mass / molar mass ....... (1)</h3>

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3 0

2 years ago

A mixture of hydrochloric and sulfuric acids is prepared so that it contains 0.315 M HCl and 0.125 M H2SO4. What volume of 0.55

Xelga [282]

<u>Answer:</u> The volume of NaOH required is 402.9 mL

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$ .....(1)

<u>For HCl:</u>

Molarity of HCl solution = 0.315 M

Volume of solution = 503.4 mL = 0.5034 L (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

$0.315M=\frac{\text{Moles of HCl}}{0.5034L}\\\\\text{Moles of HCl}=(0.315mol/L\times 0.5034L)=0.1586mol$

<u>For sulfuric acid:</u>

Molarity of sulfuric acid solution = 0.125 M

Volume of solution = 503.4 mL = 0.5034 L

Putting values in equation 1, we get:

$0.125M=\frac{\text{Moles of }H_2SO_4}{0.5034L}\\\\\text{Moles of }H_2SO_4=(0.125mol/L\times 0.5034L)=0.0630mol$

As, all of the acid is neutralized, so moles of NaOH = [0.1586 + 0.0630] moles = 0.2216 moles

Molarity of NaOH solution = 0.55 M

Moles of NaOH = 0.2216 moles

Putting values in equation 1, we get:

$0.55M=\frac{0.2216}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{0.2216}{0.55}=0.4029L=402.9mL$

Hence, the volume of NaOH required is 402.9 mL

6 0

3 years ago

What is the molarity of a 2.0 liter solution containing 58 grams of nacl?

Savatey [412]

First, need to know the formula of Molarity.
moles of solute
Molarity = ---------------------------
liters of solution

Given
2.0 liter of solution
58 grams of NaCl

Base of my research the moles of 58 grams of NaCl is 0.750 moles

Solution

0.750 moles
Molarity = ----------------------- = 0.375
2.0 L

The molarity of this solution is 0.375

4 0

3 years ago