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WITCHER [35]
2 years ago
15

Calculate the mass in grams of NaCl required to prepare 0.500 L of a 0.500 M solution.

Chemistry
1 answer:
IceJOKER [234]2 years ago
7 0

Answer:

14.61 g NaCl

Explanation:

Molarity = moles / volume of solution (litres)

0.500 = moles / 0.500 L

moles = 0.25

Molar mass of NaCl is 58.44 g NaCl /1 mol NaCl.

0.25 moles NaCl x 58.44 g NaCl /1 mol NaCl

= 14.61 g NaCl

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weqwewe [10]

Answer:

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Explanation:

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3 years ago
372x75×46+1×57×38+8=​
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Answer:

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7 0
3 years ago
How many elements have an atomic number of 42?<br><br> (Science)
pychu [463]
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5 0
3 years ago
Whitney's tidal volume, which is the volume of air that she inhales and exhales, was 0.56 L . Her tidal volume was measured at a
ipn [44]

<u>Given:</u>

Volume of air inhaled V = 0.56 L

Temperature T = 37 C = 37 +273 = 310 K

Pressure P = 744 mmHg = 744/760 = 0.979 atm

% N2 in air = 78%

<u>To determine:</u>

The moles of N2 inhaled in one breath

<u>Explanation:</u>

Step 1: Calculate the moles of air inhales

Based on the ideal gas law:

PV = nRT

where P = pressure, T = temperature, V = volume, n = # moles

R = gas constant = 0.0821 L atm/mol-K

n = PV/RT = 0.979 * 0.56/0.0821*310 = 0.0215 moles of air

Step 2: Calculate the moles of N2

It is given that air contains 78% N2

Therefore:

moles of N2 = 0.0215 * 78/100 = 0.0168 moles

Ans: moles of N2 = 0.0168


6 0
4 years ago
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