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larisa [96]
2 years ago
7

1. Reflect triangle A across the line x = 2.

Mathematics
2 answers:
romanna [79]2 years ago
7 0

Answer:

<u>Rule</u>:  Reflect the figure across the y-axis then translate the reflected figure 4 units to the right.

Step-by-step explanation:

<h3><u>Part 1</u></h3>

Points of Figure A:

(2, 2)

(8, 4)

(6, 8)

Draw a line at x = 2, then reflect each point across the line

(2, 2) → (2, 2)

(8, 4) → (-4, 4)

(6, 8) → (-2, 8)

<h3><u>Part 2</u></h3>

Reflection in the y-axis:  (x, y) → (-x, y)

As the y-values of our two figures have not changed, the first part of the rule is: <u>reflect across the y-axis</u>

If we reflect the figure across the y-axis, the points of the reflected figure are:

(-2, 2)

(-8, 4)

(-6, 8)

To bring the reflected figure back to where we want it (reflection in x = 2) we need to <u>translate the figure 4 units to the right</u>:

(-2 + 4, 2) = (2, 2)

(-8 + 4, 4) = (-4, 2)

(-6 + 4, 8) = (-2, 8)

So the final rule is:

<u>Reflect the figure across the y-axis then translate the reflected figure 4 units to the right.</u>

Vedmedyk [2.9K]2 years ago
4 0

Draw a perpendicular at x=2

Now reflect each coordinates across there

(2,2)

  • Will remain same as x=2 is on Q1 positive side

(8,4)

  • x coordinate=2-8=-6
  • y coordinate=4(same)

New coordinate (-6,4)

(6,8)

  • x coordinate=2-6=-4
  • y coordinate is same

New coordinate

  • (-4,8)
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The equation of a parabola is given.y=1/8x^2+4x+20 What are the coordinates of the focus of the parabola?
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1. Identify the focus and the directrix for 36(y+9) = (x - 5)^2 2. Identify the focus and the directrix for 20(x-8) = (y + 3)^2
Simora [160]

Problem 1

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------------------

Explanation:

The given equation can be written as 4*9(y-(-9)) = (x-5)^2

Then compare this to the form 4p(y-k) = (x-h)^2

We see that p = 9. This is the focal distance. It is the distance from the vertex to the focus along the axis of symmetry. The vertex here is (h,k) = (5,-9)

We'll start at the vertex (5,-9) and move upward 9 units to get to (5,0) which is where the focus is situated. Why did we move up? Because the original equation can be written into the form y = a(x-h)^2 + k, and it turns out that a = 1/36 in this case, which is a positive value. When 'a' is positive, the focus is above the vertex (to allow the parabola to open upward)

The directrix is the horizontal line perpendicular to the axis of symmetry. We will start at (5,-9) and move 9 units down (opposite direction as before) to arrive at y = -18 as the directrix. Note how the point (5,-18) is on this horizontal line.

================================================

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Go back to the focus and move 5 units to the left to arrive at (3,-3). Then draw a vertical line through this point to generate the directrix line x = 3

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