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Mamont248 [21]
3 years ago
8

In the chemical formula for an ionic compound, which item is written first?

Chemistry
2 answers:
Effectus [21]3 years ago
7 0
Positive ion is the correct choice
scoundrel [369]3 years ago
5 0

Answer:

a positive ion

Explanation:

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a bottle of rubbing alcohol is labeled 70%(v/v) how many milliliters of isopropyl alcohol are in a 400ml bottle of this solution
xz_007 [3.2K]
 The number of   milliliters  of  isopropyl alcohol that are  in   a 400 ml bottle  of this solution  is 280 Ml

   calculation

  % V/V =  volume of  solute/ volume  of  solution  x 100
 Let the volume  of solute  be =  y  ml
 the volume  of  solution =  400 ml
convert 70%  to fraction = 70/100

 by  substituting  the value  in the equation 

 = y  ml/  400 ml =  70/100

by cross  multiplication

100y =400 x70
100y=  28000
y= 280 ml
3 0
3 years ago
How is molecular polarity determined?
dangina [55]

Answer: Cuando esto ocurre, la molécula se considera polar. Puedes determinar la polaridad de una molécula analizando sus enlaces, probando la forma en la que interactúa con otras sustancias polares u observando su reacción a un campo electromagnético. Método 1 Dibujar las estructuras de puntos de Lewis

7 0
3 years ago
Please help me. Can you explain energy principle level?
Likurg_2 [28]
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8 0
3 years ago
Given: 2LiBr + I2 → 2LiI + Br2 Calculate the mass of bromine produced when 9.033 × 1023 particles of iodine (I2) react completel
Llana [10]

Answer:

239.7 g

Explanation:

Step 1: Write the balanced equation

2 LiBr + I₂ → 2 LiI + Br₂

Step 2: Convert the molecules of iodine to moles

We have 9.033 × 10²³ particles (molecules) of iodine. In order to convert molecules to moles, we will use the <em>Avogadro's number</em>: there are 6.022 × 10²³ molecules of iodine in 1 mole of iodine.

9.033 \times 10^{23}molecule \times \frac{1mol}{6.022 \times 10^{23}molecule} =1.500mol

Step 3: Calculate the moles of bromine produced

The <em>molar ratio of I₂ to Br₂</em> is 1:1. Then, the moles of bromine produced are 1.500 moles.

Step 4: Calculate the mass of bromine

The <em>molar mass of bromine</em> is 159.81 g/mol. The mass corresponding to 1.500 moles is:

1.500mol \times \frac{159.81g}{mol} = 239.7 g

7 0
3 years ago
Draw the conjugate base for the Brønsted-Lowry acid-base reaction that occurs when the following acid reacts with water. Show al
DanielleElmas [232]

Answer:

The structures are shown below.

Explanation:

When the acid reacts with water, it loses one proton (H⁺) and forms a base, which is the conjugate base of its acid.

The formal charge of an atom can be calculated by:

FC = X - (Y + Z/2)

Where X is the valence electrons of the neutral atom, Y is the unshared electrons, and Z is the shared electrons in the molecule.

a) When HCl deprotonates, it forms Cl⁻ as the conjugate base. The neutral atom Cl has 7 valence electrons (X), the ion has 8 unshared electrons (Y) and none shared electrons, so FC = -1 The structure is shown below in figure a.

b) When Hbr deprotonates it forms Br- as the conjugate base. The neutral atom has 7 valence electrons (X), the ion has 8 unshared electrons (Y) and none shared electrons, so FC = -1. The structure is shown below in figure b.

c) When CH3COOH loses a proton, it forms the conjugate base CH3COO⁻. The carbon as 4 valence electrons, hydrogen has 1 valence electron and oxygen has 6 valence electrons. The first carbon make simple bonds with each hydrogen and with the second carbon, and so, all the electrons are shared, and it has FC = 4 - (0 + 8/2) = 0, as so the hydrogens have FC = 1 - (0 + 2/2) = 0.

The second carbon does 1 simple bond with the first carbon, a double bond with one oxygen, and a simple bond with the other oxygen, and so doesn't have unshared electrons, and FC = 4 - (0 + 8/2) = 0.

The first oxygen does a double bond with the carbon, and so it has 4 unshared electrons, so FC = 6 - (4 + 4/2) = 0. The second oxygen does a simple bond with the carbon, and so has 5 unshared electrons, so FC = 6 - (5 + 2/2) = 0.

The structure is shown in figure c.

7 0
3 years ago
Read 2 more answers
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