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2 years ago

Symbols used in equations, together with the explanations of the symbols, are shown below. which set is correct?

Chemistry

2 answers:

vaieri [72.5K]2 years ago

3 0

Number 4 : solid product

o-na [289]2 years ago

3 0

These appear to be symbols indicating the state of the substances in a chemical equation. In that case, (g) would indicate a gaseous substance, (l) a liquid substance, (aq) a substance dissolved in water, and (s) a solid.

Thus, 3 and 4 are the correct pairs. 1 and 2 confuse the state symbols with unit symbols, and unit symbols are usually not written in chemical equations.

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Question 2

Alenkinab [10]

Answer:

1.53 atm

Explanation:

From the question given above, the following data were obtained:

Volume = constant

Initial pressure (P₁) = stp = 1 atm

Initial temperature (T₁) = 273 K

Final temperature (T₂) = 144 °C = 144 °C + 273 = 417 K

Final pressure (P₂) =?

Since the volume is constant, the final pressure can be obtained as follow:

P₁ / T₁ = P₂ / T₂

1 / 273 = P₂ / 417

Cross multiply

273 × P₂ = 417

Divide both side by 273

P₂ = 417 / 273

P₂ = 1.53 atm

Therefore, the final pressure (i.e the pressure inside the hot water bottle) is 1.53 atm.

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2 years ago

The two methods in the lab for measuring the volume of a geometric solid object are weighing it on the balance and measuring it

Yakvenalex [24]

Answer:

Measuring with a ruler and using final volume minus initial volume

Explanation:

You can measure the volume of a geometric object by measuring its sides with a ruler and calculating the volume according to the corresponding formula for each object. For example, for a rectangular prism it would be

$volume=length*width*height$

You can also measure the volume of an object by measuring how much water it displaces. To do this you have to fill a measuring cylinder with enough water for the object to be completely submerged and take note of the volume. Then, add the object and note again the volume of the water+object. The difference between both is the volume of the object.

$Volume of the object= volume of water and object - volume of water$

The advantage of the second method is that it can be used for objects with irregular shapes as long as they do not float.

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