components of the speed of the coin is given as
now the time taken by the coin to reach the plate is given by
now in order to find the height
so it is placed at 1.52 m height
A river flows from south to north at 5.4 km/hr. on the west bank of this river, a boat launches and travels perpendicular to the
1 answer:
The motion of the boat is basically a uniform motion on both directions, north-south (NS) and east-west (EW), with two constant velocities: 
and 
.
From the law of motion on the EW direction we can find the total time of the motion:
since we know
, we find
and then, we can find how far the boat went on the NS direction during this time:
From the law of motion on the EW direction we can find the total time of the motion:
since we know
and then, we can find how far the boat went on the NS direction during this time:
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Answer:
v=0.94 m/s
Explanation:
Given that
M= 5.67 kg
k= 150 N/m
m=1 kg
μ = 0.45
The maximum acceleration of upper block can be μ g.
a= μ g ( g = 10 m/s²)
The maximum acceleration of system will ω²X.
ω = natural frequency
X=maximum displacement
For top stop slipping
μ g =ω²X
We know for spring mass system natural frequency given as
By putting the values
ω = 4.47 rad/s
μ g =ω²X
By putting the values
0.45 x 10 = 4.47² X
X = 0.2 m
From energy conservation
150 x 0.2²=6.67 v²
v=0.94 m/s
This is the maximum speed of system.