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MissTica
3 years ago
5

A river flows from south to north at 5.4 km/hr. on the west bank of this river, a boat launches and travels perpendicular to the

current with a velocity of 7.6 km/hr due east. if the river is 1.4 km wide at this point, how far downstream does the boat land on the east bank of the river relative to the point it started at on the west bank?
Physics
1 answer:
Aleks [24]3 years ago
7 0
The motion of the boat is basically a uniform motion on both directions, north-south (NS) and east-west (EW), with two constant velocities: v_{SN}=5.4~km/h and v_{EW}=7.6~km/h. 
From the law of motion on the EW direction we can find the total time of the motion:
S_{EW}(t) = v_{EW} t
since we know S_{EW}=1.4~km, we find
t= \frac{S_{EW}}{v_{EW}} =0.18~h
and then, we can find how far the boat went on the NS direction during this time:
S_{NS}=v_{NS} t =5.4~km/h \cdot 0.18~h = 1~km
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Answer:

2.5N

Explanation:

since force is inversely proportional to square of the distance apart. that means the ratio of distance apart. so u have 12800×12800÷(6400××6400)=4/1

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3 years ago
An electric iron operating at 120 volts draws 10. amperes of current. how much heat energy
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The complete question is how much heat energy is delivered by the iron in 30 seconds.
Heat is given by IVt, Where I is the current in Amperes, V is the voltage, and t is the time in seconds,
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3 years ago
An eagle flying at 15 m/s has 600 J of kinetic energy. About how much is the eagles mass?
Eduardwww [97]

Answer:

5.33kg

Explanation:

Given parameters:

Velocity of eagle  = 15m/s

Kinetic energy of the eagle = 600J

Unknown:

Mass of the eagle  = ?

Solution:

The kinetic energy of any body is the energy due to the motion of a body. There are different forms of kinetic energy some of which are thermal, mechanical, electrical  energy.

The formula of kinetic energy is given as;

              Kinetic energy  = \frac{1}{2} m v²

where m is the mass, V is the velocity

   substitute the parameters in the equation;

                       600  = \frac{1}{2} x m x 15²

                     225m  = 1200

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3 0
3 years ago
A student attaches a block to a vertical spring so that the block-spring system will oscillate if the block-spring system is rel
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Answer:

Time period of the motion will remain the same while the amplitude of the motion will change

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As we know that time period of oscillation of spring block system is given as

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now we know that

M = mass of the object

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So here we know that the time period is independent of the gravity

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mg = kx

x = \frac{mg}{k}

so we can say that

Time period of the motion will remain the same while the amplitude of the motion will change

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Heck yeah i'll follow!!!!!!
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