The car is accelerating at 3 m/s² in the positive direction (to the right). By Newton's second law, the net force on the car in this direction is
∑ F = F[a] - F[f] - F[air] = ma
3100 N - 200 N - F[air] = (650 kg) (3 m/s²)
Solve for F[air] :
F[air] = 3100 N - 200 N - (650 kg) (3 m/s²)
F[air] = 3100 N - 200 N - 1950 N
F[air] = 950 N
Explanation:
As the given data is as follows.
ohm
,
ohm,
= 1200
(as 1 k ohm = 1000 m)
(a) We will calculate the maximum resistance by combining the given resistances as follows.
Max. Resistance = 
=
ohm
= 2600 ohm
or, = 2.6
ohm
Therefore, the maximum resistance you can obtain by combining these is 2.6
ohm.
(b) Now, the minimum resistance is calculated as follows.
Min. Resistance = 
= 
=
ohm
Hence, we can conclude that minimum resistance you can obtain by combining these is
ohm.
Answer:
Not possible
Explanation:
Unless there's some extra external force to keep both particles at rest after the collision, the momentum must be conserved before and after the collision.
So before the collision, 1 particle is at rest, 1 not -> total momentum is non-zero
After the collision, both particles are at rest -> total momentum is zero which is different from before.
Therefore this is not possible.
Answer:

Explanation:
<u>Coulomb's Law</u>
The force between two charged particles of charges q1 and q2 separated by a distance d is given by the Coulomb's Law formula:

Where:

q1, q2 = the objects' charge
d= The distance between the objects
We know both charges are identical, i.e. q1=q2=q. This reduces the formula to:

Since we know the force F=1 N and the distance d=1 m, let's find the common charge of the spheres solving for q:

Substituting values:


This charge corresponds to a number of electrons given by the elementary charge of the electron:

Thus, the charge of any of the spheres is:

