Question

The cart is initially at rest. Force F⃗ is applied to the cart for time Δ t, after which the car has speed v. Suppose the same force is applied for the same time to a second cart with twice the mass. Friction is negligible. Afterward, the second carts speed will be

Answer 1

Answer:

v / 2

Explanation:

Force F is applied for Δ t time so

impulse = FΔ t

impulse = m( v -u )

= m( v -0 )

= mv

If same force is applied for the same time on mass 2m

FΔ t = 2m v_x

= mv = 2m  v_x

v_x  = v / 2