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KIM [24]
3 years ago
15

The cart is initially at rest. Force F⃗ is applied to the cart for time Δ t, after which the car has speed v. Suppose the same f

orce is applied for the same time to a second cart with twice the mass. Friction is negligible. Afterward, the second carts speed will be
Physics
1 answer:
Sindrei [870]3 years ago
5 0

Answer:

v / 2

Explanation:

Force F is applied for Δ t time so

impulse = FΔ t

impulse = m( v -u )

= m( v -0 )

= mv

If same force is applied for the same time on mass 2m

FΔ t = 2m v_x

= mv = 2m  v_x

v_x  = v / 2

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Answer:

option C

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3 years ago
For copper, ρ = 8.93 g/cm3 and M = 63.5 g/mol. Assuming one free electron per copper atom, what is the drift velocity of electro
viktelen [127]

Answer:

V_d = 1.75 × 10⁻⁴ m/s

Explanation:

Given:

Density of copper, ρ = 8.93 g/cm³

mass, M = 63.5 g/mol

Radius of wire = 0.625 mm

Current, I = 3A

Area of the wire, A = \frac{\pi d^2}{4} = A = \frac{\pi 0.625^2}{4}

Now,

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V_d=\frac{J}{ne}

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V_d=\frac{2444619.925}{8.719\times 10^{28}\times (1.6\times 10^{-19})e} = 1.75 × 10⁻⁴ m/s

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