Electric power is given by:
Power = voltage x current
10000 = 15.8V
V = 633 Volts
Column A: x-axis, input, domain
Column B: y-axis, output, range
Those are other ways to describe them
hope i helped:)
r₁ = distance of point A from charge q₁ = 0.13 m
r₂ = distance of point A from charge q₂ = 0.24 m
r₃ = distance of point A from charge q₃ = 0.13 m
Electric field by charge q₁ at A is given as
E₁ = k q₁ /r₁² = (9 x 10⁹) (2.30 x 10⁻¹²)/(0.13)² = 1.225 N/C towards right
Electric field by charge q₂ at A is given as
E₂ = k q₂ /r₂² = (9 x 10⁹) (4.50 x 10⁻¹²)/(0.24)² = 0.703 N/C towards left
Since the electric field in left direction is smaller, hence the electric field by the third charge must be in left direction
Electric field at A will be zero when
E₁ = E₂ + E₃
1.225 = 0.703 + E₃
E₃ = 0.522 N/C
Electric field by charge "q₃" is given as
E₃ = k q₃ /r₃²
0.522 = (9 x 10⁹) q₃/(0.13)²
q₃ = 0.980 x 10⁻¹² C = 0.980 pC
Answer:
Explanation:
Voltage, V = 1.58 V
Power, P = 1 W
1 A.h
Charge, Q = 1 A.h = 1 x 3600 A.s = 3600 C
Power x time = Voltage x charge
1 x t = 1.58 x 3600
t = 1.58 x 3600 second
t = 1.58 hours