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4 years ago

What is the specific gravity of a concentrated sulfuric acid solution? A. 1.419 B. 1.000 C. 1.835 D. 1.263

Chemistry

2 answers:

Volgvan4 years ago

7 0

Answer: GE=1,84

Explanation:

The specific gravity (GE), also known as relative density, consists in the ratio or ratio that exists between the density of one substance and the density of another reference substance (it is usual to use water,62.428 lb/ft3 ).

When it is proposed to calculate the specific gravity using the density in pounds per cubic foot of a material such as concentrated sulfuric acid solution, the calculation would be as follows:

GE = concentrated sulfuric acid solution Density (lb / ft³) / 62.428 lb/ft3

DL is equal to 114.8674 lb / ft³. So:

GE = 114.8674 lb / ft³ / 62.4

GE = 1.840

GaryK [48]4 years ago

5 0

Hello.

Your answer would be:

It’s about 1.84

So in your case

C. 1.835 Rounded

Plz mark me brainliest

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<u>Answer:</u> The standard free energy change of formation of $S^{2-}(aq.)$ is 92.094 kJ/mol

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$K_{sp}\text{ of }Ag_2S=8\times 10^{-51}$

Relation between standard Gibbs free energy and equilibrium constant follows:

$\Delta G^o=-RT\ln K$

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$\Delta G^o$ = standard Gibbs free energy = ?

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T = temperature = $25^oC=[273+25]K=298K$

K = equilibrium constant or solubility product = $8\times 10^{-51}$

Putting values in above equation, we get:

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For the given chemical equation:

$Ag_2S(s)\rightleftharpoons 2Ag^+(aq.)+S^{2-}(aq.)$

The equation used to calculate Gibbs free change is of a reaction is:

$\Delta G^o_{rxn}=\sum [n\times \Delta G^o_f_{(product)}]-\sum [n\times \Delta G^o_f_{(reactant)}]$

The equation for the Gibbs free energy change of the above reaction is:

$\Delta G^o_{rxn}=[(2\times \Delta G^o_f_{(Ag^+(aq.))})+(1\times \Delta G^o_f_{(S^{2-}(aq.))})]-[(1\times \Delta G^o_f_{(Ag_2S(s))})]$

We are given:

$\Delta G^o_f_{(Ag_2S(s))}=-39.5kJ/mol\\\Delta G^o_f_{(Ag^+(aq.))}=77.1kJ/mol\\\Delta G^o=285.794kJ$

Putting values in above equation, we get:

$285.794=[(2\times 77.1)+(1\times \Delta G^o_f_{(S^{2-}(aq.))})]-[(1\times (-39.5))]\\\\\Delta G^o_f_{(S^{2-}(aq.))=92.094J/mol$

Hence, the standard free energy change of formation of $S^{2-}(aq.)$ is 92.094 kJ/mol

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