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aleksandr82 [10.1K]
2 years ago
5

Applying Kirchhoff’s Junction Rule, what happens to the power source and current when the parallel circuit has two branches, eac

h with a resistor, R? In one to two sentences, answer the question and explain your reasoning.
Physics
1 answer:
slamgirl [31]2 years ago
7 0

The power source voltage remains the same in a  parallel circuit,

And we'll have equal current in both lines

<h3>Kirchhoff's junction rule</h3>

Generally, Kirchhoff's junction rule states that when there is current flow at any junction of a circuit, the total sum of this current rushing into the junction amount to the same amount of current out of the Node.

Therefore, when the parallel circuit has two branches

i=i1+12

Since we have an equal resistor therefore we'll have equal current in both lines i.e i1=i2

And Voltage remains the same in a  parallel circuit

More on Voltage

brainly.com/question/14883923

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How can you find the reading of main scale and vernier scale​
anygoal [31]

Answer:

this pdf should help you out

Explanation:

Download pdf
7 0
2 years ago
What is the relationship between the masses of the objects and the gravitational force between them
irga5000 [103]

The relationship between the masses of the object and the gravitational force between them is a direct relationship

Explanation:

The gravitational force between two objects is given by  the equation:

F=G\frac{m_1 m_2}{r^2}

where

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2} is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between them

We observe that:

- The gravitational force is proportional to the masses of the two objects, m1 and m2, so if the masses increase, the force will increase as well (so, this is a direct relationship)

- The gravitational force is inversely proportional to the square of the separation between the objects, so if the distance is increased, the force will decrease (so, this is an inverse relationship)

Learn more about gravitational force here:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

6 0
3 years ago
a waves amplitude is 0.5 meters. If the amplitude is increased to 1 metro, how does its energy change
marysya [2.9K]

Answer:

The energy becomes 4 times greater.

Explanation:

We know that the energy of a wave is proportional to the square of its amplitude

E ∝ Amplitude^2

Since the original amplitude = 0.5 m

and the new amplitude becomes = 1 m

We are doubling the amplitude. This means that the new energy will be affected by a factor of 4

E_new  ∝ (2*Amplitude)^2  =

E_new ∝ 4*(Amplitude)^2  

E_new  = 4*E

5 0
3 years ago
Help!!! I need it today <br> Thank you in advance
svlad2 [7]

Answer:

 F = - k (x-xo) a graph of the weight or applied force against the elongation obtaining a line already proves Hooke's law.

Explanation:

The student wants to prove hooke's law which has the form

          F = - k (x-xo)

To do this we hang the spring in a vertical position and mark the equilibrium position on a tape measure, to simplify the calculations we can make this point zero by placing our reference system in this position.

Now for a series of known masses let's get them one by one and measure the spring elongation, building a table of weight vs elongation,

we must be careful when hanging the weights so as not to create oscillations in the spring

we look for the mass of each weight

         W = mg

          m = W / g

and we write them in a new column, we make a graph of the weight or applied force against the elongation and it should give a straight line; the slope of this line is sought, which is the spring constant.

The fact of obtaining a line already proves Hooke's law.

5 0
2 years ago
Rahim is watching his favorite football team on television. In order to work, the television must be
kvasek [131]

Answer:

it would be the cord will have the most energy at the moment.

Explanation:

...

3 0
3 years ago
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