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34kurt
3 years ago
5

In a collision that is not perfectly elastic, what happens to the mechanical energy of the system?

Physics
1 answer:
joja [24]3 years ago
5 0
C.

Thanks me later, that's my answer.
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Cart 1 of mass m is traveling with speed 2vo in the +x-direction when it has an elastic collision with cart 2 of
iogann1982 [59]

Answer:

Explanation:

Momentum conservation

m2v_0+2mv_0=mv_1+2mv_2 \quad (1/m) \quad 4v_0=v_1+2v_2\\

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\displaystyle \frac{1}{2}m(2v_0)^2+\frac{1}{2}2mv_0^2=\frac{1}{2}mv_1^2+\frac{1}{2}2mv_2^2 \quad (1/m) \quad 6v_0^2=v_1^2+2v_2^2

Solve the system

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6 0
1 year ago
A 332 kg mako shark is moving in the positive direction at a constant velocity of 2.30 m/s along the bottom of a sea when it enc
Digiron [165]

To solve this problem we will apply the concepts related to the conservation of momentum. By definition we know that the initial moment must be equivalent to the final moment of the two objects therefore

p_1 = p_2

m_1u_1+m_2u_2 = m_1v_1+ m_2v_2

Here,

m_{1,2} = Mass of each object

u_{1,2} = Initial velocity of each object

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Since the initial velocity relative to the metal tank is at rest, that velocity will be zero. And considering that in the end, the speed of the two bodies is the same, the equation would become

m_1u_1 = (m_1+m_2)v_f

Rearranging to find the velocity,

v_f = \frac{m_1u_1}{ (m_1+m_2)}

Replacing we have that,

v_f = \frac{(332)(2.3)}{ (332+19.5)}

v_f = 2.17 m/s

Therefore the velocity of the shark immediately after it swallows the tank is 2.17m/s

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3 years ago
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