Solve for the final velocity using the picture below what type of collision is this an example of

What is the difference between mass and weight?

yuradex [85]

The answer is definitely A

8 0

3 years ago

The drawing shows three particles far away from any other objects and located on a straight line. The masses of these particles

miss Akunina [59]

Formula of the gravitational force between two particles:

$F=G\frac{m_1 m_2}{r^2}$

where

$G=6.67 \cdot 10^{-11} Nm^2 kg^{-2}$ is the gravitational constant

m1 and m2 are the masses of the two particles

r is their distance

(a) particle A

The gravitational force exerted by particle B on particle A is

$F_B=G\frac{m_A m_B}{r^2}=(6.67 \cdot 10^{-11}) \frac{(340 kg)(567 kg)}{(0.500 m)^2}=5.14 \cdot 10^{-5} N$ to the right

The gravitational force exerted by particle C on particle A is

$F_C=G\frac{m_A m_C}{r^2}=(6.67 \cdot 10^{-11}) \frac{(340 kg)(139 kg)}{(0.500 m+0.250m)^2}=5.6 \cdot 10^{-6} N$ to the right

So the net gravitational force on particle A is

$F_A = F_B + F_C =5.14 \cdot 10^{-5} N+5.6 \cdot 10^{-6} N=5.7 \cdot 10^{-5} N$ to the right

(b) Particle B

The gravitational force exerted by particle A on particle B is

$F_A=G\frac{m_A m_B}{r^2}=(6.67 \cdot 10^{-11}) \frac{(340 kg)(567 kg)}{(0.500 m)^2}=-5.14 \cdot 10^{-5} N$ to the left

The gravitational force exerted by particle C on particle B is

$F_C=G\frac{m_B m_C}{r^2}=(6.67 \cdot 10^{-11}) \frac{(567 kg)(139 kg)}{(0.250 m)^2}=8.41 \cdot 10^{-5} N$ to the right

So the net gravitational force on particle B is

$F_B = F_A + F_C =-5.14 \cdot 10^{-5} N+8.41 \cdot 10^{-5} N=3.27 \cdot 10^{-5} N$ to the right

(c) Particle C

The gravitational force exerted by particle A on particle C is

$F_A=G\frac{m_A m_C}{r^2}=(6.67 \cdot 10^{-11}) \frac{(340 kg)(139 kg)}{(0.500 m+0.250m)^2}=-5.6 \cdot 10^{-6} N$ to the left

The gravitational force exerted by particle B on particle C is

$F_B=G\frac{m_B m_C}{r^2}=(6.67 \cdot 10^{-11}) \frac{(567 kg)(139 kg)}{(0.250 m)^2}=-8.41 \cdot 10^{-5} N$ to the left

So the net gravitational force on particle C is

$F_C = F_B + F_A =-8.41 \cdot 10^{-5} N-5.6 \cdot 10^{-6} N=-8.97 \cdot 10^{-5} N$ to the left

3 0

3 years ago

A scientific hypothesis must be

galben [10]

A scientific hypothesis must be testable, but there is a much stronger requirement that a testable hypothesis must meet before it can really be considered <span>scientific</span>

3 0

3 years ago

Write five ideas that you can recall about the types of important values and skills, how to set and reach goals, and different w

fenix001 [56]

Answer:

Find the ideas below.

Explanation:

1. Important values are those standards that people live by and which inspires them to act. Some of them include respect, honesty, integrity, and responsibility.

2. Important skills are those learned behaviors that help people to be more productive. There are hard and soft skills. Examples include; communication, teamwork, time management, information technology skills, etc.

3. To set and reach goals, a person must be focused, disciplined, ready to learn from others, and willing to never give up.

4. People learn in different ways and at their own pace.

5. There are four learning styles and these include; auditory, visual, kinesthetic, and reading/writing learners.

3 0

3 years ago

The presence of foreign pottery in a well-dated Egyptian context shows that this type of pottery cannot be more recent than thos

Nutka1998 [239]

Answer:

TERMINUS ANTE QUEM

Explanation: Terminus ante quem is an Archeological an a Latin term used to describe the date before which an event or events took place,it is also used to show the date before which Archeological works have been deposited in a given area.

Example, a pottery dating to the 4th century AD found on a surface would give that pottery with a terminus ante quem of the 4thcentury AD.

This type of cross dating can either be TERMINUS ANTE QUEM OR TERMINUS POST QUEM.

3 0

3 years ago