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BigorU [14]
2 years ago
14

What is the difference between reflection and refraction? What changes and what does not change.

Physics
1 answer:
wolverine [178]2 years ago
8 0

Answer:

Reflection involves a change in direction of waves when they bounce off a barrier. Refraction of waves involves a change in the direction of waves as they pass from one medium to another.

Explanation:

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What is the direction of transfer of energy in the waves produced?
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Transverse waves occur when a disturbance causes oscillationsperpendicular (at right angles) to the propagation (the direction of energy transfer). Longitudinal waves occur when the oscillations are parallel to the direction of propagation.
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Click to review the online content. Then answer the question(s) below, using complete sentences. Scroll down to view additional
Igoryamba

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Rococo art relates to an artistic style especially of the 18th century characterized by fanciful curved asymmetrical forms and elaborate ornamentation.

Explanation:

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Sarah, who has a mass of 55 kg, is riding in a car at 20 m/s. She sees a cat crossing the street and slams on the brakes! Her se
lions [1.4K]

Answer:

-2200 N

Explanation:

Here we can use the impulse theorem, which states that the impulse exerted on Sarah (product of force and duration of collision) is equal to Sarah's change in momentum:

I=\Delta p\\F \Delta t = m \Delta v

where

F is the average force

\Delta t is the duration of the collision

m is the mass

\Delta v is the change in velocity

In this problem:

m = 55 kg

\Delta v = 0-20 = -20 m/s

\Delta t = 0.5 s

Solving the formula, we find the force exerted by the seatbelt on Sarah:

F=\frac{m\Delta v}{\Delta t}=\frac{(55)(-20)}{0.5}=-2200 N

And the negative sign means the direction is opposite to that of Sarah's initial motion.

6 0
3 years ago
A hanging wire made of an alloy of titanium with diameter 0.05 cm is initially 2.7 m long. When a 15 kg mass is hung from it, th
Svet_ta [14]

Answer:

Explanation:

Young's modulus of elasticity Y = stress / strain

stress = force / cross sectional area

= weight of 15 kg / π r²

= 15 x 9.8 / 3.14 x ( .025 x 10⁻² )²

stress = 74.9 x 10⁷ N / m²

strain = Δ L / L , Δ L is change in length and L is original length

Putting the values

strain = .0168 / 2.7 =.006222

Young's modulus of elasticity Y  = 74.9 x 10⁷ / .006222

= 120.88 x 10⁹ N / m² .

8 0
3 years ago
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