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bearhunter [10]
3 years ago
5

An object floats on water with 80% of its volume below the surface. the same object when placed in another liquid floats on that

liquid with 72% of its volume below the surface. determine the density of the unknown fluid.
Physics
1 answer:
GarryVolchara [31]3 years ago
8 0
0.9g/cm cubed, this is my full answer however i have to write at least 20 characters so this is filler :)
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The answer is D velocity is speed w a direction

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A schematic can tell an electrician that the switches are normally
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The correct answer is Option B) Open.

A schematic can tell an electrician that the switches are normally open

until the sensor senses smoke.

<h3>What is a schematic diagram?</h3>

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2 years ago
A wave transfers _____ from the source outward in the direction of wave motion.
DerKrebs [107]

A wave transfers energy from the source outward in the direction of wave motion.

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3 years ago
If an arrow is shot upward on the moon with a velocity of 58 m/s, its height (in meters) after t seconds is given by H = 58t − 0
Alex73 [517]

Answer:

a) v = 54.7m/s

b) v = (58 - 1.66a) m/s

c) t = 69.9 s

d) v = -58.0 m/s

Explanation:

Given;

The height equation of the arrow;

H = 58t - 0.83t^2

(a) Find the velocity of the arrow after two seconds. m/s;

The velocity of the arrow v can be given as dH/dt, the change in height per unit time.

v = dH/dt = 58 - 2(0.83t) ......1

At t = 2 seconds

v = dH/dt = 58 - 2(0.83×2)

v = 54.7m/s

(b) Find the velocity of the arrow when t = a. m/s

Substituting t = a into equation 1

v = 58 - 2(0.83×a)

v = (58 - 1.66a) m/s

(c) When will the arrow hit the surface? (Round your answer to one decimal place.) t = s

the time when H = 0

Substituting H = 0, we have;

H = 58t - 0.83t^2 = 0

0.83t^2 = 58t

0.83t = 58

t = 58/0.83

t = 69.9 s

(d) With what velocity will the arrow hit the surface? m/s

from equation 1;

v = dH/dt = 58 - 2(0.83t)

Substituting t = 69.9s

v = 58 - 2(0.83×69.9)

v = -58.0 m/s

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Answer:

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