Answer:
17.5g/cm3
Explanation:
find the slope of the line
Answer:
The total displacement from the starting point is 1.5 m.
Explanation:
You need to sum and substract, depending on the movement (to the right, sum; to the left, substract).
First, it moves 4.3 m right and return 1.1 m. So the new distance from the starting point is 3.2 m.
Second, it moves 6.3 m right, so the new distance is 9.5 m.
Finally it moves 8 m to the left, so 9.5 m - 8 m= 1.5 m.
Summarizing, at the end the squirrel is 1.5 m from its starting point.
Explanation:
beacuse light is mixture of many different colours,each with different frequency
If a mass m is attached to an ideal massless spring and has a period of t, then the period of the system when the mass is 2m is
.
Calculation:
Step-1:
It is given that a mass m is attached to an ideal massless spring and the period of the system is t. It is required to find the period when the mass is doubled.
The time it takes an object to complete one oscillation and return to its initial position is measured in terms of a period, or T.
It is known that the period is calculated as,

Here m is the mass of the object, and k is the spring constant.
Step-2:
Thus the period of the system with the first mass is,

The period of the system with the second mass is,

Then the period of the system with the second mass is
times more than the period of the system with the first mass.
Learn more about period of a spring-mass system here,
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