First the element has to be stable. One chooses the easiest way to make the element stable. for example : Al has 13 electrons and you want to make it stable, you consider the outermost electrons where in AL the are three so it is easier for Al to lose three than to gain five
Answer:
A. 433 years and 63 days
B. Iodine
C. 0.125mg
D. 1.00mg
Explanation:
A. Americium
The formula of a radioactive decay constant half life is t = 0.693/k
Where k is the decay constant.
For americium, k = 0.0016
t = 0.693/0.0016 = 433.125 apprx 433 years
For iodine, k = 0.011
Half life = 0.693/0.011 = 63 days.
B. Iodine decays at a faster rate.
C. After three half lives
For both, first half life yields a mass of 0.5mg, next yields 0.25mg, next yield 0.125mg
D. 1.00mg still remains.
Half life is high for both so the decay after one day is insignificant.
The metals. Primarily the left side
Answer: NaNO3 (Sodium Trioxonitrate (V) )
Explanation:
The equation of the reaction is; HNO3 + NaOH -----> H2O + NaNO3
