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Agata [3.3K]
3 years ago
10

Using the diagram shown, what is the magnitude of the resultant of these three forces?

Physics
1 answer:
amid [387]3 years ago
5 0

Explanation:

The x component of the resultant force is the sum of the x components of the individual forces.

Fₓ = 65.0 cos 30° − 20.0 sin 20° − 30.0

Fₓ = 19.5

The y component of the resultant force is the sum of the y components of the individual forces.

Fᵧ = 65.0 sin 30° − 20.0 cos 20°

Fᵧ = 13.7

The magnitude is found with Pythagorean theorem:

F² = Fₓ² + Fᵧ²

F² = (19.5)² + (13.7)²

F = 23.8

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An atom is made up of which of the following?
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A 1.2 kg ball drops vertically onto a floor from a height of 32 m, and rebounds with an initial speed of 10 m/s.
iren [92.7K]

Explanation:

Given that,

Mass of the ball, m = 1.2 kg

Initial speed of the ball, u = 10 m/s

Height of the floor from ground, h = 32 m

(a) Let v is the final speed of the ball. It can be calculated using the conservation of energy as :

\dfrac{1}{2}mv^2=mgh

v=\sqrt{2gh}

v=\sqrt{2\times 9.8\times 32}

v = -25.04 m/s (negative as it rebounds)

The impulse acting on the ball is equal to the change in momentum. It can be calculated as :

J=m(v-u)

J=1.2\times (-25.04-10)

J = -42.048 kg-m/s

(b) Time of contact, t = 0.02 s

Let F is the average force on the floor from by the ball. Impulse acting on an object is given by :

J=\dfrac{F}{t}

F=J\times t

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F = 0.8409 N

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5 0
2 years ago
Although these quantities vary from one type of cell to another, a cell can be 1.9 μm in diameter with a cell wall 60 nm thick.
DaniilM [7]

Answer: 2(10)^{-9} mg

Explanation:

We know the total diameter of the cell (assumed spherical) is:

d=1.9\mu m=1.9(10)^{-6} m

Then its total radius r=\frac{d}{2}=\frac{1.9(10)^{-6} m}{2}=9.5(10)^{-7} m

On the other hand, we know the thickness of the cell wall is r_{t}=60 nm= 60(10)^{-9} m and its density is the same as water (\rho=997 kg/m^{3}).

Since density is the relation between the mass m and the volume V:

\rho=\frac{m}{V}

The mass is: m=\rho V (1)

Now if we are talking about this cell as a thin spherical shell, its volume will be:

V=\frac{4}{3}\pi R^{3} (2)

Where  R=r-r_{w}=9.5(10)^{-7} m - 60(10)^{-9} m

Then:

V=\frac{4}{3}\pi (9.5(10)^{-7} m - 60(10)^{-9} m)^{3} (3)

V=2.952(10)^{-18} m^{3} (4)

Substituting (4) in (1):

m=(997 kg/m^{3})(2.952(10)^{-18} m^{3}) (5)

m=2.94(10)^{-15} kg (6)

Knowing 1 kg=1000 g and 1 mg=0.001 g:

m=2.94(10)^{-15} kg=2(10)^{-9} mg

7 0
3 years ago
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