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cricket20 [7]
3 years ago
15

Plz help i beg, veryyy confused :)

Physics
1 answer:
pav-90 [236]3 years ago
3 0
Displacement is distance in one particular direction. Distance is the route taken without worrying about the direction.
To find the displacement draw a straight line from the start point to the end point. Measure the length and use the scale to find the real distance.
Ask me if you need more help.
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assume that in an unpolished floor a lady us pushing a 40 kg box to the left with an applied force of 192 N. find the sum of for
Vesnalui [34]
The sum of force is 7,680...............
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2 years ago
places with continental climates typically have _______ summers and ________ winters warm; cool hot; cool warm; cold hot; cold
ipn [44]
Places with continental climates typically have hot summers and cold winters. As compared to places with mild climates, places with continental climates tend to experience the two extremes when it comes to the seasons. Summers can get very hot, and winters can get very cold. 
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3 years ago
I NEED HELP ASAP<br>please please please​
raketka [301]

Answer:

B AND D

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6 0
3 years ago
Read 2 more answers
A projectile of mass m is fired straight upward from the surface of an airless planet of radius R and mass M with an initial spe
motikmotik

Answer:

K = G Mm / 9R

Explanation:

Expression for escape velocity V_e = \sqrt{\frac{2GM}{R} }

Kinetic energy at the surface = 1/2 m V_e ²

= 1/2 x m x 2GM/R

GMm/R

Potential energy at the surface

= - GMm/R

Total energy = 0

At height 9R ( 8R from the surface )

potential energy

= - G Mm / 9R

Kinetic energy = K

Total energy will be zero according to law of conservation of mechanical energy

so

K  - G Mm / 9R = 0

K = G Mm / 9R

6 0
3 years ago
A 40-kg rock is dropped from an elevation of 10 m. What is the velocity of the rock when it is 5-m from the ground?
ivolga24 [154]

Answer:

Explanation:

Given

mass of rock m=40\ kg

Elevation of Rock h=10\ m

Distance traveled by rock with time

h=ut+\frac{1}{2}at^2

where, u=initial velocity

t=time

a=acceleration

here initial velocity is zero

when rock is 5 m from ground then it has traveled a distance of 5 m from top because total height is 10 m

5=0\times t+\frac{1}{2}(9.8)(t^2)

t^2=\frac{10}{9.8}

t=1.004\approx 1\ s

velocity at this time

v=u+at

v=0+9.8\times 1.004

v=9.83\ m/s

6 0
3 years ago
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