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4 years ago

Plz help i beg, veryyy confused :)

Physics

1 answer:

pav-90 [236]4 years ago

3 0

Displacement is distance in one particular direction. Distance is the route taken without worrying about the direction.
To find the displacement draw a straight line from the start point to the end point. Measure the length and use the scale to find the real distance.
Ask me if you need more help.

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A 24-cm-diameter vertical cylinder is sealed at the top by a frictionless 15 kg piston. The piston is 90 cm above the bottom whe

abruzzese [7]

Answer:

(A) $P_i=3249.41\ Pa$

(B) $V_f=0.3358\ m$

Explanation:

Given:

diameter of the cylinder, $d= 0.24\ m$

mass of piston sealing on the top, $m_p=15\ kg$

initial temperature of the piston, $T_i=315+273= 588\ K$

initial height of piston, $h_i=0.9\ m$

atmospheric pressure on the piston, $p_a=1 atm=101325\ Pa$

(A)

Initial pressure of gas is the pressure balanced by the weight of piston:

$P_i=\frac{m_p.g}{\pi.d^2\div 4}$

$P_i=\frac{15\times 9.8}{\pi\times (0.24^2\div 4)}$

$P_i=3249.41\ Pa$

Which is gauge pressure because it is measured with respect to the atmospheric pressure.

(B)

Given:

Final temperature, $T_f=18+273=291\ K$

Now, volume of air initially in the cylinder:

$V_i=\pi.d.h_i$

$V_i=\pi\times 0.24\times 0.9$

$V_i=0.6786\ m^3$

Using gas law:

$\frac{P_i V_i}{T_i}= \frac{P_f V_f}{T_f}$ ........................................(1)

∵In every condition of equilibrium the gas pressure will be balanced by the weight of the piston so it is an isobaric transition.

∴ $P_i=P_f$

Hence eq. (1) is reduced to:

$\frac{V_i}{T_i}= \frac{V_f}{T_f}$

putting respective values:

$\frac{0.6786}{588}= \frac{V_f}{291}$

$V_f=0.3358\ m$

6 0

4 years ago

Astronauts aboard the ISS move at about 8000 m/s, relative to us when we look upward.How long does an astronaut need to stay abo

Luba_88 [7]

Answer:

#_time = 7.5 10⁴ s

Explanation:

In order for the astronaut to be younger than the people on earth, it follows that the speed of light has a constant speed in vacuum (c = 3 108 m / s), therefore with the expressions of special relativity we have.

t = $\frac{t_p}{ \sqrt{1- (v/c)^2} }$

where t_p is the person's own time in an immobile reference frame,

$t_{p} = t \sqrt{1 - (\frac{v}{c})^2 }$

let's calculate

we assume that the speed of the space station is constant

$t_p = 1 \sqrt{1 - \frac{8 \ 10^3}{3 \ 10^8} }$

$t_p = 1 \sqrt{1- 2.6666 \ 10^{-5}}$

t_ = 0.99998666657 s

therefore the time change is

Δt = t - t_p

Δt = 1 - 0.9998666657

Δt = 1.3333 10⁻⁵ s

this is the delay in each second, therefore we can use a direct rule of proportions. If Δt was delayed every second, how much second (#_time) is needed for a total delay of Δt = 1 s

#_time = 1 / Δt

#_time = $\frac{1}{1.3333 \ 10^{-5}}$

#_time = 7.5 10⁴ s

5 0

3 years ago

A parallel-plate capacitor consists of two plates, each with an area of 27 cm^2 separated by 3.0 mm. The charge on the capacitor

aev [14]

Answer:

Explanation:

Capacity of a parallel plate capacitor C = ε₀ A/ d

ε₀ is permittivity whose value is 8.85 x 10⁻¹² , A is plate area and d is distance between plate.

C =( 8.85 X10⁻¹² X 27 X 10⁻⁴ ) / 3 X 10⁻³

= 79.65 X 10⁻¹³ F.

potential diff between plate = Charge / capacity

= 4.8 X 10⁻⁹ / 79.65 X 10⁻¹³

= 601 V

Electric field = V/d

= 601 / 3 x 10⁻³

= 2 x 10⁵ N/C

Force on proton

= charge x electric field

1.6 x 10⁻¹⁹ x 2 x 10⁵

= 3.2 x 10⁻¹⁴

Acceleration a = force / mass

= 3.2 x 10⁻¹⁴ / 1.67 x 10⁻²⁷

= 1.9 x 10¹³ m s⁻²

Distance travelled by proton = 3 x 10⁻³

3 x 10⁻³ = 1/2 a t²

t = $\sqrt{\frac{3\times2\times10^{-3}}{1.9\times10^{13}} }$

t = 1.77 x 10⁻⁸ s

6 0

4 years ago

The only force acting on a 2.5 kg canister that is moving in an xy plane has a magnitude of 3.0 N. The canister initially has a

Effectus [21]

Answer:44.58 J

Explanation:

mass of block $\left ( m\right )=2.5 kg$

Force magnitude=3 N

Initial velocity = $2.3\hat{i} m/s$

Final velocity= $6.4\hat{j} m/s$

Initial Kinetic Energy= $\frac{1}{2}mv^2$

= $\frac{1}{2}\times 2.5\times 2.3^2=6.612 J$

Final Kinetic Energy= $\frac{1}{2}mv^2$

= $\frac{1}{2}\times 2.5\times 6.4^2=51.2 J$

Work Done =Final -Initial Kinetic energy=51.2-6.612=44.58 J

4 0

3 years ago

Based on all we know about the terrestrial worlds, what single factor appears to play the most important role in a terrestrial p

Archy [21]

Based on all we know about the terrestrial worlds, the single factor appears to play the most important role in a terrestrial planet's geological destiny is size size of terrestrial planet .

According to the question

Terrestrial Planets:

They belongs to a class of planets that are like the earth

Geological destiny :

Geology is biological destiny: Whatever minerals land or are deposited in a place determine what or who can make a living there millions of years later

Based on all we know about the terrestrial worlds, what single factor appears to play the most important role in a terrestrial planet's geological destiny

i.e

The size of terrestrial planet is one of the factors to play the most important role in a terrestrial planet's geological destiny

which determines how long the planet can retain internal heat, which drives geological activity because Smaller worlds cool off faster and harden earlier .

Hence, Based on all we know about the terrestrial worlds, the single factor appears to play the most important role in a terrestrial planet's geological destiny is size size of terrestrial planet .

To know more about terrestrial here:

brainly.com/question/13490379

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6 0

2 years ago