Answer:
126 kmh⁻¹
Explanation:
We can simply solve this by applying motion equations
where
v - final velocity
u - initial velocity
a-acceleration
t - time
v = u + at
<em>= 25 + 5×2 = 35 ms⁻¹</em>
<em> = (35/1000)×3600 = 126 kmh⁻¹</em>
5N westward, acting on the student
A
C = (F-32)*5/9 = 73*5/9 = 40.55555
since the answers are spread apart, technically you can just estimate by doing -32
and then /2
since 5/9 is close to 1/2
12 coloumbs
Q = IT
I= 3A, T=4s
Q = 3×4 =12coloumbs