Calculate the specific heat of a substance when 63j of energy are transferred as heat to an 8.0 g sample to raise it temperature
2 answers:
Answer : The specific heat of substance is 0.30 J/g.K
Explanation :
Formula used :
or,
where,
Q = heat = 63 J
m = mass of substance = 8.0 g
= specific heat of substance = ?
= initial temperature = 314 K
= final temperature = 340 K
Now put all the given value in the above formula, we get:
Therefore, the specific heat of substance is 0.30 J/g.K
You might be interested in
The molecule with higher dipole moment is COFH because the geometry of the molecule in the COF2 nearly cancel the dipolar moment of each other. To be more clear:
The dipolar moment is the vectorial sum of all bond moments in the molecule or dipolar moment of each bond. The dipolar moment of a molecule with three or more atoms is determined by bond polarity as their geometry.
COF2 has a trigonal planar structure which are symmetric. The electronegativity of oxygen is slightly different regarding fluor. So as you can see in the image, the electronic density is specially displaced to the fluor atoms, but either to the oxygen atom.
COFH has a trigonal structure but differs from COF2 because there is an hydrogen who is donating it's electronic density, so in this zone the electronic density is less than over oxygen or fluor. That makes bond angles be different between them.
