As consecutive odd numbers differ by two (example: 3, 5, 7), the first odd number can be expressed as 2n + 1, the next can be found by adding two to the first to get 2n + 1 + 2 which simplifies to 2n + 3. Finally the expression for the third consecutive odd integer can be found by adding two to the previous, 2n + 3, to get 2n + 5. Adding these three together and setting them equal to your sum gets the equation
2n + 1 + 2n + 3 + 2n + 5 = 63
Combine like terms and solve For n.
Once you have n, you must substitute it back into your three expressions (2n + 1, 2n + 3, 2n + 5) to find the three odd integers.
Hope this helps :)
½ = v; multiply the divisor to remove the variable from the denominator.
To “cancel out the the 8 you would multiply by 8 on both sides and then you would be left with 48=-w. With that you would find the opposite of 48 and w and w=-48
Answer:
see explanation
Step-by-step explanation:
3x and 144 are adjacent angles on a straight line and sum to 180°
3x + 144 = 180 ( subtract 144 from both sides )
3x = 36 ← value of 3x
divide both sides by 3
x = 12
and
2y - 5 and 95 are vertically opposite angles and are congruent, so
2y - 5 = 95 ← value of 2y - 5
add 5 to both sides
2y = 100 ( divide both sides by 2 )
y = 50
Then
x + y = 12 + 50 = 62
Answer:
x = 17, MN = 11
Step-by-step explanation:
Given 2 secants from an external point to a circle, then
The product of the external part and the whole of one secant is equal to the product of the external part and the whole of the other secant.
(5)
7(7 + x) = 8(8 + 13) = 8 × 21 = 168 ( divide both sides by 7 )
7 + x = 24 ( subtract 7 from both sides )
x = 17
(6)
9(9 + 2x - 7) = 10(10 + 8)
9(2x + 2) = 10 × 18 = 180 ( divide both sides by 9 )
2x + 2 = 20 ( subtract 2 from both sides )
2x = 18 ( divide both sides by 2 )
x = 9
Then
MN = 2x - 7 = 2(9) - 7 = 18 - 7 = 11