Answer:
A) 15.0 years
Explanation:
Due to the distance to the star system is in light-year units, we can compute the time by using:
then, Rob will take to complete the trip about 15 light-years.
hope this helps!!
Answer:
Fc=5253
N
Explanation:
Answer:
Fc=5253
N
Explanation:
sequel to the question given, this question would have taken precedence:
"The 86.0 kg pilot does not want the centripetal acceleration to exceed 6.23 times free-fall acceleration. a) Find the minimum radius of the plane’s path. Answer in units of m."
so we derive centripetal acceleration first
ac (centripetal acceleration) = v^2/r
make r the subject of the equation
r= v^2/ac
ac is 6.23*g which is 9.81
v is 101m/s
substituing the parameters into the equation, to get the radius
(101^2)/(6.23*9.81) = 167m
Now for part
( b) there are two forces namely, the centripetal and the weight of the pilot, but the seat is exerting the same force back due to newtons third law.
he net force that maintains circular motion exerted on the pilot by the seat belts, the friction against the seat, and so forth is the centripetal force.
Fc (Centripetal Force) = m*v^2/r
So (86kg* 101^2)/(167) =
Fc=5253
N
Answer:
88.89kg
Explanation:
The formula for mass is m=F/a. If we plug in the values, we get m=400N/4.5m/s^2. The mass is 88.89kg. We know that the unit is in kg because one newton (N) is 1kg*m/s^2. The m/s^2 is cancelled out by the acceleration, and we are left with kg.
Answer:
Explanation:
Impedence of the circuit = peak voltage / peak current
= 5.8 / 51 x 10⁻³
= 113.725 ohm.
1 / wC =113.725
w = 1 / (113.725 x 22 x 10⁻⁹ )
= 10⁹ / 2.5 x 10³
=10⁶ / 2.5
40 x 10⁴
frequency n = 40 x 10⁴ / 2 x 3.14
6.37 x 10⁴ Hz.
b ) charge on the capacitor = 1 C
V = Q / C
= Charge / capacitor
= 1 / 22 x 10⁻⁹
4.54 x 10⁷ V.
Answer:
10.89 J.
Explanation:
The following data were obtained from the question:
Mass (m) = 12.5 kg
Velocity (v) = 1.32 m/s
Work done =?
To obtain the workdone, we shall determine the kinetic energy of the object since work and energy has the same unit of measurement. This is illustrated below:
Mass (m) = 12.5 kg
Velocity (v) = 1.32 m/s
Kinetic energy (K.E) =?
K.E = ½mv²
K.E = ½ × 12.5 × 1.32²
K.E = 6.25 × 1.7424
K.E = 10.89 J
The kinetic energy of the object is 10.89 J. Hence, the workdone in bringing the object to rest is 10.89 J.
