What is the angular diameter (in arcseconds) of an object that has a linear diameter of 75 cm and a distance of 2 km?

Physics

1 answer:

charle [14.2K]3 years ago

8 0

Answer:

The angular diameter is 77.35 arc-seconds.

Explanation:

The angular diameter, as shown in the figure, is the angle $x$ subtended by the the diameter of the object.

Before we do the calculation, we first convert everything to meters.

The diameter of the of the object in meters is

75cm =0.75m,

and the distance to the object in meters is

2 km = 2000 m.

Now, from trigonometry we get:

$tan (\frac{x}{2} )= \dfrac{radius}{length} = \dfrac{0.75/2}{2000} \\\\\dfrac{x}{2} = tan^{-1}(\dfrac{0.75/2}{2000})\\\\\dfrac{x}{2}= 0.0107\\\\\boxed{x= 0.0215^o}$

and since 1 degree = 3600 arc-seconds, $x$ in arc-seconds is

$x= 0.0215*3600 \\\\\boxed{x= 77.35''}$

You might be interested in

What units do physicists use to measure heat energy and electrical energy?

vagabundo [1.1K]

<span>Physicists use certain units to measure heat energy and electrical energy:

- Joule (Watt sec )
- Watt - hour
- Kilowatt- hour
- Calorie

Hope this helps!

</span>

6 0

3 years ago

A plane traveling north at 100.0 km/h through the air gets caught in a 40.0 km/h crosswind blowing west. This turbulence caused

Nonamiya [84]

Answer:

The velocity $\vec{v}_{c/g}$ of the cart with respect to the ground is

$\vec{v}_{c/g}=-40\hat{x}+80\hat{y}\, km/h$

if we consider North the positive y-direction and East the positive x-direction.

Explanation:

We have for relative motion the following expression:

$\vec{v}_{c/g}=\vec{v}_{c/p}+\vec{v}_{p/g}$

Where $\vec{v}_{c/g}$ is the velocity of the cart with respect to the ground, $\vec{v}_{c/p}$ is the velocity of the cart with respect to the plane and $\vec{v}_{p/g}$ is the velocity of the plane with respect to the ground.