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3 years ago

What is the angular diameter (in arcseconds) of an object that has a linear diameter of 75 cm and a distance of 2 km?

Physics

1 answer:

charle [14.2K]3 years ago

8 0

Answer:

The angular diameter is 77.35 arc-seconds.

Explanation:

The angular diameter, as shown in the figure, is the angle $x$ subtended by the the diameter of the object.

Before we do the calculation, we first convert everything to meters.

The diameter of the of the object in meters is

75cm =0.75m,

and the distance to the object in meters is

2 km = 2000 m.

Now, from trigonometry we get:

$tan (\frac{x}{2} )= \dfrac{radius}{length} = \dfrac{0.75/2}{2000} \\\\\dfrac{x}{2} = tan^{-1}(\dfrac{0.75/2}{2000})\\\\\dfrac{x}{2}= 0.0107\\\\\boxed{x= 0.0215^o}$

and since 1 degree = 3600 arc-seconds, $x$ in arc-seconds is

$x= 0.0215*3600 \\\\\boxed{x= 77.35''}$

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In April 1974, Steve Prefontaine completed a 10.0 km race in a time of 27 min , 43.6 s . Suppose "Pre" was at the 7.43 km mark a

Novay_Z [31]

Answer:

Acceleration, a = 0.101 m/s²

Explanation:

Average speed = total distance / total time.

At the 7.43km mark, total distance = 7.43km or 7430m

Total time = 25 * 60 s = 1500s

Average speed = 7430m/1500s = 4.95m/s

He then covers (10 - 7.43)km = 2.57 km = 2570 m

in t = 27m43.6s - 25min = 2m43.6s = 163.6 s

Then he accelerates for 60 s, and maintains this velocity V, for the remaining (163.6 - 60)s = 103.6 s.

From V = u + at; V = 4.95m/s + a *60s

Distance covered while accelerating is

s = ut + ½at² = 4.95m/s * 60s + ½ a *(60s)² = 297m + a*1800s²

Distance covered while at constant velocity, v after accelerating is

D = velocity * time

Where v = 4.95m/s + a*60s

D = (4.95m/s + a*60s) * 103.6s = 512.82m + a*6216s²

Total distance covered after initial 7.43 km, S + D = 2570 m, so

2570 m = 297m + a*1800s² + 512.82m + a*6216s²

2570 = 809.82 + a*8016

a = 809.82m / 8016s² = 0.101 m/s²

8 0

3 years ago

The movement of particles from high to low concentration. True or False

Digiron [165]

Question:

Diffusion is the movement of particles from high to low concentration. True or False

Answer:

True.

Explanation:

Diffusion is a process that allows the movement of substance or particles in and out of cells through a semipermeable membrane.

Diffusion is a process that allows the spread or movement of particles from the region of higher concentration to a region of lower concentration through a semipermeable membrane.

Diffusion only occurs in gases and solution but not in solids, it also occurs only where particles can move freely.

Note: When particles move from the region of higher concentration to a lower concentration, it gives room for even, uniform and random distribution of particles.

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3 years ago

If you want the ball to land in your hand when it comes back down, should you toss the ball straight upward, in a forward direct

denpristay [2]

Straight upward

the ball moves in the forward direction with your walking speed at all times. If you want the ball to land in your hand when it comes back down, you should toss the ball straight upward.

<h3>What is Projectile motion ?</h3>

Projectile motion is the motion of an object thrown (projected) into the air.

After the initial force that launches the object, it only experiences the force of gravity. The object is called a projectile, and its path is called its trajectory

A projectile can be a thrown ball, a bullet or a springboard diver ... Except for air resistance, the forward velocity of any projectile is constant and is equal to the initial velocity when it was released.

Learn more about Projectile motion here:

brainly.com/question/27116954

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7 0

2 years ago

HELP WILL GIVE BRAINLIEST IF CORRECT

PolarNik [594]

Answer:

the answer is 1.35. Have a nice day!!

3 0

3 years ago

Read 2 more answers