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Crank
3 years ago
5

The boiling point of a substance is affected by

Chemistry
1 answer:
Artyom0805 [142]3 years ago
7 0

Answer:

The mass of the substance

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The chemical standard for the quantity of a mole is based on which substance?
alexandr402 [8]
A mole is mean the atomic number of 12 grams of carbon 12.
3 0
4 years ago
What is the kb of the base po−34 given that a 0. 48m solution of the base has a ph of 12. 70? the equation described by the kb v
podryga [215]

The equation described by the kb value is 5.21 x 10^-^3.

The potential of Hydrogen is what pH is formally known as. The negative logarithm of the concentration of H+ ions is known as pH. Thus, the definition of pH as the amount of hydrogen is provided. The hydrogen ion concentration in a solution is described by the pH scale, which also serves as a gauge for the solution's acidity or basicity.

Assuming  PO₄³⁻ (the phosphate anion).

PO₄³- + H₂O ==> HPO₄²⁻ + OH⁻

Kb = [HPO₄²⁻][OH⁻] / [PO₄³⁻]

We can find the [OH⁻] from the pH of 12.70.

pH + pOH = 14

14.0 - 12.7 = 1.3 = pOH

[OH] = 1x10^-^1^.^3

[OH-] = 5.0x10^-^2 M

[HPO₄²⁻] = 5.0x10^-^2 M

Kb = (5.0x10^-^2)2 / 0.48

     = 2.5x10^-^3 / 0.48

Kb = 5.21 x 10^-^3

Learn more about pH here:

brainly.com/question/8758541

#SPJ4

3 0
1 year ago
A liquid is heated until boils.
ella [17]
C. The thermometer reads 100
7 0
3 years ago
What is the molality of nitric acid in a concentrated solution of nitric acid (68.0% HNO3 by mass)? (a) Outline the steps necess
RoseWind [281]

Answer:

33.8 m

Explanation:

(a) We want to know the molality of nitric acid in a concentrated solution of nitric acid (68.0% HNO₃ by mass).

Step 1: Determine the mass of HNO₃ and water in 100 grams of solution.

Step 2: Convert the mass of HNO₃ to moles.

Step 3: Convert the mass of water to kilograms.

Step 4: Calculate the molality.

(b)

Step 1

In 100 g of solution, there are 68.0 g of HNO₃ and 100 g - 68.0 g = 32.0 g of water.

Step 2

The molar mass of HNO₃ is 63.01 g/mol. The moles corresponding to 68.0 g are:

68.0 g × (1 mol/63.01 g) = 1.08 mol

Step 3

The mass of water is 32.0 g = 0.0320 kg

Step 4

The molality of HNO₃ is:

m = moles of solute / kilograms of solvent

m = 1.08 mol / 0.0320 kg

m = 33.8 m

5 0
4 years ago
Read 2 more answers
What's the mass in grams of 0.334 moles of sucrose (C12H22O11)?
Sonbull [250]

Answer:

114.23g

Explanation:

Mass = xg

Mole = 0.334 mol

Molar mass of Sucrose

(C = 12, H = 1, O = 16)

C12H22O11

(12×12)+(1×22)+(16×11)

144 + 22 + 176

342g/mol

Mass = No of mole × Molar mass

Mass = 0.334 × 342

Mass = 114.228

Mass ≈ 114.23g

3 0
3 years ago
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