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Natali5045456 [20]
2 years ago
8

Can someone please help me with this....?

Chemistry
1 answer:
N76 [4]2 years ago
4 0

Answer:

Explanation:

The answer is D

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Determine the electron geometry, molecular geometry, and idealized bond angles for each molecule. In which cases do you expect d
Ira Lisetskai [31]

Answer:

The electron geometry, molecular geometry and idealized bond angles for these molecules respectively are:

a. CF4: tetrahedral, tetrahedral and 109.5 degrees

b. NF3 tetrahedral, trigonal pyramidal and 102.5 degrees

c. OF2 tetrahedral, angular and 103 degrees

d. H2S tetrahedral, angular and 92.1 degrees

Explanation:

The electron geometry considers the bound atoms and unbound electron pairs to determine the geometry. The four molecules have four bound atoms and/or unbound electrons pairs, thus they have a tetrahedral geometry. On the other hand, the molecular geometry only considers the position of bound atoms to determine the geometry.

Between H3O and H2O, H2O has a smaller bond angle due to the two unbound electron pairs. The bond angle decrease as the number of unbound electron pairs increases in every molecule.

CO2 and CCl4 are both nonpolar because of the 3D geometry of the molecule. Each individual bond is polar but both molecules have symmetrical geometry so the dipole bonds are canceled.

CH3F  is a polar molecule because the dipole between the C-H and C-F bonds are differents thus, besides the symmetrical geometry the dipole bonds are not canceled.

8 0
2 years ago
A) which substances are the products? ______________________________
FromTheMoon [43]
In a chemical reaction the products are found at the right of the equation, the products are what is being made once the reaction is complete. On the right side if the chemical equation is the reactants or starting materials, these are the substances that are combined to provide a product on the right side of the equation. Since I am not able to see the equation, just simple add all the carbons that are on the left and that will tell you how many carbons there are in total on the reactant side and if you add all of the carbons on the right side it will let you know how many carbons there are on the product side. The same steps can be taken for Oxygen.
I am unable to answer the last one as I need more information. But basically the law states that any system for which matter and energy cannot be transfer as it is a closed system, then since the system's mass can't change then it cannot be added or subtracted
5 0
3 years ago
Which characteristic is not common to outer planets? Question 3 options: They support rung systems They have no solid surface Th
Dominik [7]

Answer:

They have no solid surface.

Explanation:

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6 0
2 years ago
Read 2 more answers
An aqueous solution containing 10 g of an optically pure compound was diluted to 500 mL with water and was found to have a speci
lapo4ka [179]

Answer:

<u>Optical purity = 76.9231 %</u>

<u>Specific rotation of mixture = - 97.6923 °</u>

Explanation:

The mass of the racemic mixture = 3 g

It means it contains R enantiomer = 1.5 g

S enantiomer = 1.5 g

Amount of Pure R = 10 g

Total R = 11.5 g

Total volume = 500 mL + 500 mL = 1000 mL = 1 L

[R] = 11.5 g/L

[S] = 1.5 g/L

Enantiomeric excess = \frac {Excess}{Total\ Concentration}\times 100 = \frac {11.5-1.5}{11.5+1.5}\times 100 = 76.9231 %

<u>Optical purity = 76.9231 %</u>

Also,

Optical purity = \frac {optical\ rotation\ of\ mixture}{optical\ rotation\ of\ pure\ enantiomer}\times 100

Optical rotation of pure enantiomer = −127 °

76.9231=\frac {optical\ rotation\ of\ mixture}{-127^0}\times 100

<u>Specific rotation of mixture = - 97.6923 °</u>

6 0
3 years ago
The curiosity is important in the progress of science because it
nordsb [41]
It it important because it makes people wonder how things work and are made which makes it so they want to move forward with experiments <span />
3 0
3 years ago
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