Explanation:
cl2 = 50/71
mole of cl2 = 0.704
no.of molecules = mole × avagadro no.
no of molecules = 0.704× 6.022×10²³
no. of molecules = 4.23×10²³
Answer:
+1.76 V
Explanation:
Ecell = Ecathode - Eanode
= -0.19 - (-1.95) = + 1.76 V
Answer:What is the question
Explanation:
<u>Answer:</u> The amount of heat required to warm given amount of water is 470.9 kJ
<u>Explanation:</u>
To calculate the mass of water, we use the equation:

Density of water = 1 g/mL
Volume of water = 1.50 L = 1500 mL (Conversion factor: 1 L = 1000 mL)
Putting values in above equation, we get:

To calculate the heat absorbed by the water, we use the equation:

where,
q = heat absorbed
m = mass of water = 1500 g
c = heat capacity of water = 4.186 J/g°C
= change in temperature = 
Putting values in above equation, we get:

Hence, the amount of heat required to warm given amount of water is 470.9 kJ