1) If the volume of a container is increased, the temperature increases. 2) If the volume of a container is decreased, the temperature decreases. This means that the volume of a gas is directly proportional to its temperature. ... If the amount of gas in a container is increased, the volume increases.
<span>The minimum amount of energy needed to get a chemical reaction started is called the activation energy.
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Answer:
a) pH = 13.176
b) pH = 13
c) pH = 12.574
d) pH = 7.0
e) pH = 1.46
f) pH = 1.21
Explanation:
HBr + NaOH ↔ NaBr + H2O
∴ equivalent point:
⇒ mol acid = mol base
⇒ (Va)*(0.150mol/L) = (0.025L)*(0.150mol/L)
⇒ Va = 0.025 L
a) before addition acid:
⇒ <em>C </em>NaOH = 0.150 M
⇒ [ OH- ] = 0.150 M
⇒ pOH = - Log ( 0.150 )
⇒ pOH = 0.824
⇒ pH = 14 - pOH
⇒ pH = 13.176
b) after addition 5mL HBr:
⇒ <em>C </em>NaOH = (( 0.025)*(0.150) - (0.005)*(0.150)) / (0.025 + 0.005) = 0.1 M
⇒ <em>C </em>HBr = (0.005)*(0.150) / ( 0.03 ) = 0.025 M
⇒ [ OH- ] = 0.1 M
⇒ pOH = 1
⇒ pH = 13
c) after addition 15mL HBr:
⇒ <em>C </em>NaOH = ((0.025)*(0.150) - (0.015)*(0.150 ))/(0.04) = 0.0375 M
⇒ <em>C </em>HBr = ((0.015)*(0.150))/(0.04) = 0.0563 M
⇒ [ OH- ] = 0.0375 M
⇒ pOH = 1.426
⇒ pH = 12.574
d) after addition 25mL HBr:
equivalent point:
⇒ [ OH- ] = [ H3O+ ]
⇒ Kw = 1 E-14 = [ H3O+ ] * [ OH- ] = [ H3O+ ]²
⇒ [ H3O+ ] = 1 E-7
⇒ pH = 7.0
d) after addition 40mL HBr:
⇒ <em>C</em> HBr = ((0.04)*(0.150) - (0.025)*(0.150)) / (0.04 + 0.025) = 0.035 M
⇒ [ H3O+ ] = 0.035 M
⇒ pH = 1.46
d) after addition 60mL HBr:
⇒ <em>C</em> HBr = ((0.06)*(0.150) - (0.025)*(0.150)) / (0.06+0.025) = 0.062 M
⇒ [ H3O+ ] = 0.062 M
⇒ pH = 1.21
Answer:
There are 3.01x10²³ molecules of sucrose
Explanation:
In order to calculate the number of molecules of any atom or compound, we need to use the Avogadro number which is 6.02x10²³. This number could represent atoms or molecules of any mole of compound or atom.
In other words, 1 mole of a certain atom or compound has 6.02x10²³ molecules or atoms.
we have 0.5 moles of sucrose, all we just need to do is a simple rule of 3:
If 1 mole contains 6.02x10²³ molecules
then 0.5 moles will contain:
n° molecules = 0.5 * 6.02x10²³ / 1
<h2>
n° molecules = 3.01x10²³ molecules of sucrose</h2>
Hope this helps
Answer:
Explanation:
In stoichiometry, molar mass is used to convert between the mass of a substance and how many moles of a substance.
