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Tanzania [10]
2 years ago
6

If the soccer ball has a mass of 284g, and gravitational force is 9.81 m/s2 on Earth, what is the weight of the soccer ball?

Physics
1 answer:
bagirrra123 [75]2 years ago
4 0

Answer:

  1. <u>2.79 N</u>
  2. <u>8.34 N</u>
  3. <u>Watermelon</u>

Explanation:

<u>Weight of soccer ball</u>

  • Weight = mass (in kg) × gravitational force
  • Weight = 284 x 10⁻³ x 9.81
  • Weight = 0.284 x 9.81
  • Weight = <u>2.79 N</u> (approximately)

<u>Weight of watermelon</u>

  • Weight = mass (in kg) x gravitational force
  • Weight = 850 x 10⁻³ x 9.81
  • Weight = 0.85 x 9.81
  • Weight = <u>8.34 N</u> (approximately)

As the <u>watermelon</u> has more weight, it will hit the ground first.

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Given a second class lever with a distance of 5.00 feet from the fulcrum to the effort and a distance of 33.0 inches from the re
leva [86]

Answer:

The correct answer is C. 45.5 lbs.

Explanation:

In a second class lever, the load is located between the point in which the force is exerted and the fulcrum.

The formula for any problem involving a lever is:

F_ed_e=F_ld_l

Where F_e is the effort force, d_e is the total length of the lever, F_l is the load that can be lifted and d_l is the distance between the point of the effort and the fulcrum.

The parameter of the formula that you need is F_l:

F_l=\frac{F_ed_e}{d_l}

The conversion from feet to inches is 1 ft is equal to 12 inches. In this case, 5 ft are equal to 60 inches.

F_l=\frac{25*60}{33}

F_l=45.5 lbs

7 0
4 years ago
To tugboats pull a disabled supertanker. Each tug exerts a constant force of 1.50•10^6 N, one at an angle 19.0° west of north, a
irina1246 [14]

Answer:

Work done by a tug boat, W = 1.735 x 10⁸ J

Explanation:

Given,

The of each tugboat, F = 1.5 x 10⁶ N

The angle of each tugboat forms with the resultant force, θ = 19°

The displacement of the supertanker, s = 710 m

The individual tugboat will be responsible for the displacement, d = 710/2

                                                                                                               = 355 m

The displacement component in each tugboat direction = 355 · sin θ meter

Therefore, the work done by each tugboat is

                                           W = F x S    joules

Substituting the values in the above equation

                                            W = 1.5 x 10⁶  x  355 · sin θ

                                                = 1.735 x 10⁸ J

Hence, the work done by each tugboat is, W = 1.735 x 10⁸ J                        

6 0
3 years ago
Ecologically speaking, which is bigger, a population or a community? Explain.
exis [7]

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3 0
3 years ago
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Which circuit has the larger equivalent resistance: a circuit with two 10 ohm resistors connected in parallel or a circuit with
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Answer:

A circuit with two 10 ohm resistors connected in series.

Explanation:

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The formula for the equivalent resistance for resistors in series is

Rt = R1 + R2  So Rt= 10 + 10 = 20

6 0
3 years ago
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emmasim [6.3K]
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I hope I've helped!
4 0
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