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GrogVix [38]
3 years ago
7

Demand for a certain product is forecast to be 800 units per month, averaged over all 12 months of the year. The product follows

a seasonal pattern, for which the January monthly index is 1.25. What is the seasonally-adjusted sales forecast for January?
Physics
1 answer:
Aloiza [94]3 years ago
6 0

Explanation:

The given data is as follows.

       Demand for a certain product = 800 units/month

       January monthly index = 1.25

Since, we have to calculate seasonally adjusted sales forecast for January. Hence, it will be calculated as follows.

            Adjusted forecast = Demand × Monthly index

                                           = 800 × 1.25

                                           = 1000

Thus, we can conclude that adjusted forecast for January is 1000 units.

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"a horn emits a frequency of 1000 HZ. A 14 m/s wind is blowing toward a listener. What is the frequency of the sound heard by th
Semenov [28]

Answer:

 f_L = 1000 Hz

Explanation:

given,

speed of wind, = 14 m/s

frequency of horn,f_s = 1000 Hz

speed of sound,V = 344 m/s

frequency heard by the listener

using Doppler effect

f_L = \dfrac{v+v_L}{v+v_s}f_s

f_L is the frequency of the sound heard by the listener

f_s is the frequency of sound emitted by the listener

V is the speed of sound

v_L is the speed of listener

v_s is the speed of source

now,

considering the frame of reference in which wind is at rest now, both listener and the source will be moving at 14 m/s

 f_L = \dfrac{v+14}{v+14}\times 1000

now on solving we will get

 f_L = 1000 Hz

hence, the frequency heard by the listener is equal to  1000 Hz

 

7 0
3 years ago
A crane raises a 12,000 N marble sculpture at a constant velocity onto a pedestal 1.5 m above the ground outside an art museum.
Simora [160]

For the work, applicate formula:

\boxed{\boxed{\green{\bf{W = F\times d}}}}

According our data:

  • Replacing:

W = 12000 N * 1,5 m

  • Resolving:

W = 18000 J

The work done is <u>18000 Joules.</u>

7 0
3 years ago
If an object has two forces that are equal in magnitude, but acting on it in opposite directions, what are some possible things
Oksi-84 [34.3K]

Answer: The body will be in a position of rest

Explanation:

Since both forces are equal and acting in opposite direction on the body. It will make the body to be in a state of rest or equilibrium because the sum of the forces acting in the body will be zero.

5 0
3 years ago
Why there is tides in sea and ocean
AleksandrR [38]

Answer:

<em>    Tides are the rise and fall of sea levels. Tides occur due to the gravitational forces exerted on the Earth by moon, and to a lesser extent, the sun. That's why tides occur in ocean or sea.</em>

Hope this helps

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7 0
4 years ago
A solid conducting sphere with radius R that carries positive charge Q is concentric with a very thin insulating shell of radius
Nostrana [21]

Explanation:

Gauss Law relates the distribution of electric charge to the resulting electric field.

Applying Gauss's Law,

                              EA = Q / ε₀

Where:

E is the magnitude of the electric field,

A is the cross-sectional area of the conducting sphere,

Q is the positive charge

ε₀ is the permittivity

We be considering cases for the specified regions.

<u>Case 1</u>: When r < R

The electric field is zero, since the enclosed charge is equal to zero

                                            E(r) = 0

<u>Case 2</u>: When R < r < 2R

The enclosed charge equals to Q, then the electric field equals;

                              E(4πr²) = Q / ε₀

                              E = Q / 4πε₀r²

                              E = KQ /r²

Constant K = 1 / 4πε₀ = 9.0 × 10⁹ Nm²/C²

<u>Case 3</u>: When r > 2R    

The enclosed charge equals to Q, then the electric field equals;

                               E(4πr²) = 2Q / ε₀

                               E = 2Q / 4πε₀r²

                               E = 2KQ /r²        

4 0
3 years ago
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