Question

What is the magnetic flux density (B-field) at a distance of 0.36 m from a long, straight wire carrying a current of 3.8 A in air? Give your answer in units of tesla.

Answer 1

Answer:

The magnetic flux density is $2.11\times10^{-6}\ T$

Explanation:

Given that,

Distance = 0.36 m

Current = 3.8 A

We need to calculate the magnetic flux density

Using formula of magnetic field

$B =\dfrac{\mu_{0}I}{2r}$

Where,

r = radius

I = current

Put the value into the formula

$B =\dfrac{4\pi\times10^{-7}\times3.8}{2\times\pi\times0.36}$

$B=2.11\times10^{-6}\ T$

Hence, The magnetic flux density is $2.11\times10^{-6}\ T$