The distance covered is simply the length of the entire trip, which is 12m + 16m, or 28m.
The displacement is the distance from the starting point to the ending point along with the direction of the net motion. The dog walks 12m east then 16m west, so its resultant displacement is 4m west.
Answer:
The horse is going at 12.72 m/s speed.
Explanation:
The initial speed of the horse (u) = 3 m/s
The acceleration of the horse (a)= 5 m/
The displacement( it is assumed it is moving in a straight line)(s)= 15.3 m
Applying the second equation of motion to find out the time,



Solving this quadratic equation, we get time(t)=1.945 s, the other negative time is neglected.
Now applying first equation of motion, to find out the final velocity,



v=12.72 m/s
The horse travels at a speed of 12.72 m/s after covering the given distance.
W, because as time is moving up at a consistent rate the speed is as well, creating the straight line.
Answer:
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Explanation:
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