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amid [387]
2 years ago
12

what is the name of the area around a charged object where the object can exert a force on other charged objects?

Physics
1 answer:
shusha [124]2 years ago
4 0

Answer:

An electric field is a region around a charged object where the object's electric force is exerted on other charged objects. Electric fields get weaker the farther away they are from the charge. An electric field is invisible. You can use the field line to represent it.

Explanation:

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What will be the pressure exerterd by the 0bject if 4000n is acting on an area of 50msqure
Ivahew [28]
<h3>Given, </h3>

Force,F = 4000 N

Area,a = 50 m²

<h3>We know that, </h3>

Pressure = Force/Area

★ Putting the values in the above formula,we get:

\sf \rightarrow \: pressure =  \dfrac{4000}{50}

\sf \rightarrow pressure = 80 \: N {m}^{ - 2}

7 0
3 years ago
Radio telescopes are said to "listen" to space because...
almond37 [142]

Answer:

2 they detect radio waves

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3 years ago
1. Which object is farthest from the origin at t=2sec
Stolb23 [73]

Answer:

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6 0
2 years ago
Help
Blizzard [7]
We can approach this in another way.
We know that sin(∅) = height / hypotenuse.

Thus, for x, height is 1 and hypotenuse is 3. Using Pythagoras theorem,
3² = 1² + b²
b = √8
cos(x) = b/hypotenuse
cos(x) = √8 / 3

Now, lets consider y:
sec(y) = 1 / cos(y) = 1 / base / hypotenuse = hypotenuse / base
The hypotenuse is 25 and the base is 24. We again apply Pythagoras theorem to find the third side, which works out to be:
height = 7
sin(y) = height / hypotenuse
sin(y) = 7/25

Now, sin(x + y) =
sin(x)cos(y) + sin(y)cos(x)
= (1/3)(24/25) + (√8 / 3)(7/25)
= 8/25 + 7√8/75
= (24 + 14√2) / 75
6 0
3 years ago
Read 2 more answers
A laser is placed at the point $(3,5)$. The laser beam travels in a straight line. Larry wants the beam to hit and bounce off th
Black_prince [1.1K]

Answer:

4units

Explanation:

To calculate the total distance the beam will travel along this path, you will use the formula for calculating the distance between two coordinates expressed as;

D = √(x2-x1)²+(y2-y1)²

Given the coordinate points

(3,5) and (7,5)

Substitute

D = √(7-3)²+(5-5)²

D = √(7-3)²+0²

D = √4²

D = √16

D = 4

Hence the total distance the beam will travel along this path is 4units

6 0
3 years ago
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