Answer:
18 teeth/inch
Explanation:
Given that: i. driver gear has 8 teeth and diametral pitch of 6 teeth/inch.
ii. follower gear has 24 teeth.
Let the followers diametral pitch be represented by x.
Then,
8 teeth ⇒ 6 teeth/inch
24 teeth ⇒ x teeth/inch
So that;
x = 
= 
= 18 teeth/inch
The diametral is 18 teeth/inch
Answer:
a) 42.08 ft/sec
b) 3366.33 ft³/sec
c) 0.235
d) 18.225 ft
e) 3.80 ft
Explanation:
Given:
b = 80ft
y1 = 1 ft
y2 = 10ft
a) Let's take the formula:

1 + 8f² = (20+1)²
= 8f² = 440
f² = 55
f = 7.416
For velocity of the faster moving flow, we have :
V1 = 42.08 ft/sec
b) the flow rate will be calculated as
Q = VA
VA = V1 * b *y1
= 42.08 * 80 * 1
= 3366.66 ft³/sec
c) The Froude number of the sub-critical flow.
V2.A2 = 3366.66
Where A2 = 80ft * 10ft
Solving for V2, we have:
= 4.208 ft/sec
Froude number, F2 =
F2 = 0.235
d)
= 18.225ft
e) for critical depth, we use :
= 3.80 ft
Answer: y = x * 1dollars - 30dollars
Explanation:
Giving that the delivery cost in dollar is potent for all x > = 50 pounds of wght
Y = (x - 50)*1 dollar + c ...equ 1
Y = delivery cost equation in dollars
x = weigt of baggage for delivery
c = 20dollars = down payment for the first 50 pound weight of baggage
Equ 1 becomes
Y = (x)dollars - 50 dollars + 20 dollars
Y = (x) dollars -30 dollars
Answer:
The answer is "+9.05 kw"
Explanation:
In the given question some information is missing which can be given in the following attachment.
The solution to this question can be defined as follows:
let assume that flow is from 1 to 2 then
Q= 1kw
m=0.1 kg/s
From the steady flow energy equation is:
![m\{n_1+ \frac{v^2_1}{z}+ gz_1 \}+Q= m \{h_2+ \frac{v^2_2}{2}+ gz_2\}+w\\\\\ change \ energy\\\\0.1[1.005 \times 800]-1= 0.01[1.005\times 700]+w\\\\w= +9.05 \ kw\\\\](https://tex.z-dn.net/?f=m%5C%7Bn_1%2B%20%5Cfrac%7Bv%5E2_1%7D%7Bz%7D%2B%20gz_1%20%5C%7D%2BQ%3D%20m%20%5C%7Bh_2%2B%20%5Cfrac%7Bv%5E2_2%7D%7B2%7D%2B%20gz_2%5C%7D%2Bw%5C%5C%5C%5C%5C%20change%20%5C%20energy%5C%5C%5C%5C0.1%5B1.005%20%5Ctimes%20800%5D-1%3D%200.01%5B1.005%5Ctimes%20700%5D%2Bw%5C%5C%5C%5Cw%3D%20%2B9.05%20%5C%20kw%5C%5C%5C%5C)
If the sign of the work performed is positive, it means the work is done on the surrounding so, that the expected direction of the flow is right.