Answer: the mass flow rate of concentrated brine out of the process is 46,666.669 kg/hr
Explanation:
F, W and B are the fresh feed, brine and total water obtained
w = 2 x 10^4 L/h
we know that
F = W + B
we substitute
F = 2 x 10^4 + B
F = 20000 + B .................EQUA 1
solute
0.035F = 0.05B
B = 0.035F/0.05
B = 0.7F
now we substitute value of B in equation 1
F = 20000 + 0.7F
0.3F = 20000
F = 20000/0.3
F = 66666.67 kg/hr
B = 0.7F
B = 0.7 * F
B = 0.7 * 66666.67
B = 46,666.669 kg/hr
the mass flow rate of concentrated brine out of the process is 46,666.669 kg/hr
Answer:
w ( mass flow rate of air ) = 3.16 kg/s
Explanation:
<u>Determine the mass flow rate of air </u>
mass flow rate of water = 1.5 kg/s
Height at which air enters the cooling tower = 1m
velocity of air entering at 1 m = 20 m/s
Height at which air leaves the cooling tower = 7 m
attached below is a detailed solution of the problem
Answer:
The voltage needed to accelerate the electron beam is 2.46 x 10^16 Volts
Explanation:
The rate of electron flow is given as:
q = 1015 electrons per second
The total current is given by:
Total Current = (Rate of electron flow)(Charge on one electron)
Total Current = I = (1015 electrons/s)(1.6 x 10^-19 C/electron)
I = 1.624 x 10^-16 A
Now, we know that electric power is given as:
Electric Power = Current x Voltage
P = IV
V = P/I
V = 4 W/1.624 X 10^-16 A
<u>V = 2.46 x 10^16 Volts</u>
Answer:
A sand bed is necessary because it provides a refractory bottom for molten metal
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