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3 years ago

Fe2O3 + 3H2 → 2Fe + 3H20

Chemistry

1 answer:

Bingel [31]3 years ago

7 0

Hope this helps
U can ask any doubt if u have

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Free brainiest! the first person who makes me blush or makes me want to kiss you.

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Explanation:Do you like to draw coz you put the D in raw

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3 years ago

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When a test instrument is calibrated, does its accuracy, precision, or reliability improve?

My name is Ann [436]

The answer is accuracy.

That is when a test instrument is calibrated, its accuracy is improved. That is the result comes more close to what it is.

The other factor will not be improved that is its reliability and precision remains the same.

So the answer is accuracy is improved when a test instrument is calibrated.

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3 years ago

Identify the state of matter in between C&D.

ladessa [460]

Answer:

Here's the answer in order

Explanation:

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3 years ago

When 8.2 grams of LiBr are dissolved in enough water to create a 150-gram solution, what is the solution's concentration, expres

Dahasolnce [82]

Answer:

5.46% is the percent by mass concentration of the solution.

Explanation:

Mass of LiBr= 8.2 g(Solute)

Mass of solution = 150 g (Solution)

Mass of solution = Mass of solute + Mass of solvent

Mass of solute < Mass of solvent (Always)

Mass of water = 150 g - 8.2 g = 141.8 g (solvent)

Mass percentage is given as:

$\frac{\text{mass of solute}}{\text{mass of solution}}\times 100$

$Mass\%=\frac{8.2 g}{150 g}\times 100=5.46\%$

5.46% is the percent by mass concentration of the solution.

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3 years ago

4. Arrange the following substances in order of increasing boiling point: CH3CH2OH, HOCH2CH2OH, CH3CH2Cl , and ClCH2CH2OH A. CH3

Studentka2010 [4]

Answer: Option (B) is the correct answer.

Explanation:

A molecules that will have more number of hydrogen bonding will has highest boiling point because to break the hydrogen bonds high heat needs to be provided.

So, in the molecule $HOCH_{2}CH_{2}OH$ there is presence of two alcoholic groups. Hence, it will have strongest hydrogen bonding as compared to the rest of molecules.

In the molecule $ClCH_{2}CH_{2}OH$ there will be hydrogen bonding and dipole-dipole interactions. Hence, it boiling point will be slightly less than $HOCH_{2}CH_{2}OH$ .

In the molecule $CH_{3}CH_{2}OH$ , there will be only hydrogen bonding. Hence, its boiling point is less than $ClCH_{2}CH_{2}OH$ .

In the molecule $CH_{3}CH_{2}Cl$ , there is no hydrogen bonding but there will be only dipole-dipole interactions. Hence, its boiling point will be the least.

Therefore, we can conclude that increasing order of boiling point will be as follows.

$CH_{3}CH_{2}Cl$ < $CH_{3}CH_{2}OH$ < $ClCH_{2}CH_{2}OH$ < $HOCH_{2}CH_{2}OH$

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3 years ago