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Readme [11.4K]
2 years ago
10

What is the mass percent of a sugar solution when 489 grams of sugar is combined with 877 grams of water?​

Chemistry
1 answer:
natka813 [3]2 years ago
4 0
The sugar solution was made by mixing 12 grams of water
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REALLY NEED HELP!!! Chemistry
kicyunya [14]

Answer:

C.) 2

Explanation:

The pH equation is:

pH = -log[H⁺]

In this equation, [H⁺] is the molarity of the acid. In this case, the acid is HCl. Molarity can be found using the equation:

Molarity (M) = moles / volume (L)

Since you were given moles and volume, you can find the molarity of HCl.

Molarity = moles / volume

Molarity = 0.01 moles / 1.00 L

Molarity = 0.01 M

Now, you can plug the molarity of the acid into the pH equation.

pH = -log[H⁺]

pH = -log[0.01]

pH = 2

3 0
2 years ago
Can we all agree chemistry is hard lol
Dmitry_Shevchenko [17]

Yes, I agree.

Chemistry can be difficult.

5 0
3 years ago
Convert 1.350 atm into mmHg
Daniel [21]

Answer:

1026

Explanation:

Pressure

1.35

Standard atmosphere

=

1026

Millimetre of mercury

Formula

multiply the pressure value by 760

7 0
3 years ago
Read 2 more answers
My homework said"Solve using the standard algorithm. Check your quotient and remainder by using multiplication and addition."
Harman [31]
84 divided by 2 = 42.

2 goes into 8 four times, so there would be your 4.
 Then 2 goes into 2 one time, and there would be your 2.

You check your answer by multiplying 42 by 2, which would give you, 84.
5 0
3 years ago
Read 2 more answers
Nitrogen gas is being withdrawn at the rate of 4.5 g/s from a 0.15-m3 cylinder, initially containing the gas at a pressure of 10
faust18 [17]

Answer:

Final temperature = 152.57K,

Pressure = 0.6907 bar.

dT/dt = - 1,151 K/s.

Explanation:

The first thing to do here is to write out the equation for mass balance as given below:

dN/dt = N -------------------------------------------------------------------------------------------(1).

N = P/T, then, substitute the values given in the question into:

d[p/T]/ dt = [- 4.5/28 × 8.314]/0.15 = - 8.9 × 10⁻⁵ bar/K.s.

Thus, there is the need to integrate, Integrate [p/T]f = 10/320 - 8.9 × 10⁻⁵ bar/K.s. ------------------------------------(2).

NB; fT = final temperature, fP = final pressure and iT = initial temperature.

Also, [ fT]³⁰/₈.₃₁₄/ [fP] = [iT]³⁰/₈.₃₁₄/ Pi] = [ 320]³⁰/₈.₃₁₄/ 10.

Therefore, [fT]³⁰/₈.₃₁₄ = 109.52 × 10⁶.

Final temperature=  [fP]³⁰/₈.₃₁₄ × 169.05.

Note that fP/ [fP]³⁰/₈.₃₁₄ × 169.05 = 10/320 - 8.9 × 10⁻⁵.

Therefore, [fP]¹ ⁻ ³⁰/₈.₃₁₄ = 0.7651.

Hence, Final temperature = 152.57K,

Pressure = 0.6907 bar

dT/ dt = N[RT]² / Cv . PV.

R = 30 - 8.314 = 21.86 J/mol K.

Then, the rate of change of the gas temperature at this time = dT/dt = - 1,151 K/s.

4 0
2 years ago
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