The term amphoteric describes a substance that can act as both an acid and a base.
 
        
             
        
        
        
Does anyone know the answer?
        
                    
             
        
        
        
Mangenese is the element which have 25 protons
        
             
        
        
        
Complete Question 
You determine that it takes 26.0 mL of base to neutralize a sample of your unknown acid solution. The pH of the solution was 7.82 when exactly 13 mL of base had been added, you notice that the concentration of the unknown acid was 0.1 M. What is the pKa of your unknown acid?
Answer:
The pK_a value is 
 
Explanation:
From the question we are told 
     The volume of base is  
      The pH of solution is  
       The concentration of the acid is 
From the pH we can see that the titration is between a strong base and a weak acid 
  Let assume that the the volume of acid is  
 Generally the concentration of base 
                     
 Substituting value  
                      
                     
When 13mL of the base is added a buffer is formed 
The chemical equation of the reaction is 
            
Now before the reaction the number of mole of base is  
             ![No \ of \ moles[N_B]  =  C_B * V_B](https://tex.z-dn.net/?f=No%20%5C%20of%20%5C%20moles%5BN_B%5D%20%20%3D%20%20C_B%20%2A%20V_B)
Substituting value  
                     
                          
     
                                  
Now before the reaction the number of mole of acid is  
             
Substituting value  
                     
                          
Now after the reaction the number of moles of  base is  zero  i.e has been used up 
     this mathematically represented as 
                          
     The  number of moles of acid is  
              
                    
 The pH of this reaction can be mathematically represented as 
                  ![pH  = pK_a + log \frac{[base]}{[acid]}](https://tex.z-dn.net/?f=pH%20%20%3D%20pK_a%20%2B%20log%20%5Cfrac%7B%5Bbase%5D%7D%7B%5Bacid%5D%7D)
 Substituting values 
                   