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jasenka [17]
3 years ago
10

Importancia de las disoluciones en la vida cotidiana

Chemistry
1 answer:
Tomtit [17]3 years ago
4 0

Las disoluciones son fundamentales para que se lleven a cabo las reacciones químicas que sustentan la vida. Esta es una mezcla de dos o más sustancias.

<h3>Disoluciones</h3>

Una disolución se refiere a una mezcla entre dos o más sustancias puras que da lugar a una mezcla homogénea de las mismas.

Una disolución está compuesta por al menos una sustancia conocida como disolvente (por ejemplo, agua) y al menos susutancia conocida como soluto (por ejemplo, sal).

Las disoluciones son fundamentales para  una gran variedad de procesos biológicos requeridos para sustentar la vida y las reacciones metabólicas asociadas a estos procesos.

Aprende más sobre disoluciones aquí:

brainly.com/question/24003174

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Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/m
koban [17]

Here is the full question:

Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/min, and the circulated air is then pumped out at the same rate. If there is an initial concentration of 0.2% carbon dioxide, determine the subsequent amount in the room at any time.

What is the concentration at 10 minutes? (Round your answer to three decimal places.

Answer:

0.046 %

Explanation:

The rate-in;

R_{in} = \frac{0.04}{100}*2000

R_{in} = 0.8

The rate-out

R_{out} = \frac{A}{6000}*2000

R_{out} = \frac{A}{3}

We can say that:

\frac{dA}{dt}= 0.8-\frac{A}{3}

where;

A(0)= 0.2% × 6000

A(0)= 0.002 × 6000

A(0)= 12

\frac{dA}{dt} +\frac{A}{3} =0.8

Integration of the above linear equation =

e^{\int\limits \frac {1}{3}dt } = e^{\frac{1}{3}t

so we have:

e^{\frac{1}{3}t}\frac{dA}{dt}} +\frac{1}{3}e^{\frac{1}{3}t}A = 0.8e^{\frac{1}{3}t

\frac{d}{dt}[e^{\frac{1}{3}t}A] = 0.8e^{\frac{1}{3}t

Ae^{\frac{1}{3}t} =2.4e\frac{1}{3}t +C

∴ A(t) = 2.4 +Ce^{-\frac{1}{3}t

Since A(0) = 12

Then;

12 =2.4 + Ce^{-\frac{1}{3}}(0)

C= 12-2.4

C =9.6

Hence;

A(t) = 2.4 +9.6e^{-\frac{t}{3}}

A(0) = 2.4 +9.6e^{-\frac{10}{3}}

A(t) = 2.74

∴ the concentration at 10 minutes is ;

=  \frac{2.74}{6000}*100%

= 0.0456667 %

= 0.046% to three decimal places

7 0
3 years ago
How many liters of oxygen gas are there in 45.0g O, at 0 degrees C and 1 atm of pressure? make sure to round to the correct numb
ZanzabumX [31]

Answer:

You can use the pdf to help you

Explanation:

Download pdf
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3 years ago
The amount of force needed to keep a 10 kg box moving at a constant
boyakko [2]

Answer:

ON

Explanation:

Frictional force is a force that opposes the motion of body. It is because of friction that motion can be controlled and even walking is made possible.

Now, on a frictionless surface, there is no opposition to motion. Therefore, to keep the body moving there is no force required.

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What is an electrolyte in an electrochemical cell?
Svet_ta [14]

Answer:

An electrolytic cell uses electrical energy to drive a non-spontaneous redox reaction. An electrolytic cell is a kind of electrochemical cell. ... The electrolyte is usually a solution of water or other solvents in which ions are dissolved. Molten salts such as sodium chloride are also electrolytes.

Explanation:

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The pH of a solution can be calculated using which formula?
VikaD [51]

Answer:

The formula for calculating pH is pH=−log[H_3O+ ]

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The pH Formula can also be expressed as

PH= - log[H+ ]

5 0
3 years ago
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