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jasenka [17]
2 years ago
10

Importancia de las disoluciones en la vida cotidiana

Chemistry
1 answer:
Tomtit [17]2 years ago
4 0

Las disoluciones son fundamentales para que se lleven a cabo las reacciones químicas que sustentan la vida. Esta es una mezcla de dos o más sustancias.

<h3>Disoluciones</h3>

Una disolución se refiere a una mezcla entre dos o más sustancias puras que da lugar a una mezcla homogénea de las mismas.

Una disolución está compuesta por al menos una sustancia conocida como disolvente (por ejemplo, agua) y al menos susutancia conocida como soluto (por ejemplo, sal).

Las disoluciones son fundamentales para  una gran variedad de procesos biológicos requeridos para sustentar la vida y las reacciones metabólicas asociadas a estos procesos.

Aprende más sobre disoluciones aquí:

brainly.com/question/24003174

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Explanation:

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Integrated Problem 01.69 With current spectroscopic techniques, chemists are generally able to determine the structure of an unk
Gnesinka [82]

a or c becuse it means you should answer it very wiseley

5 0
3 years ago
Write a balanced half-reaction describing the reduction of aqueous vanadium(V) cations to aqueous vanadium(I) cations.
11Alexandr11 [23.1K]

Explanation:

Reduction is a chemical reaction in which electrons are gained by one of the atoms taking part in the reaction and lowering of an oxidation state of that atom.

Reduction takes place at the cathode.

In aqueous, vanadium(V) is present in +5 oxidation state which on reduction changes to vanadium(I) with +1 oxidation state.

The half reaction is :

V^{5+}(aq)+4e^- \rightarrow V^{1+}(aq)


5 0
3 years ago
Read 2 more answers
3. Nitrogen, when combined with oxygen, can form various oxides. 3.5 g of nitrogen gas is burned in oxygen to form 11.5 g of an
Pavel [41]

Answer:

A.

Explanation:

5 0
3 years ago
A 222 N force is required to keep an object moving along a circular path with a diameter of 11.6 m at a speed of 7.60 m/s. What
Arte-miy333 [17]

Answer:

m=22.3\ kg

Explanation:

The expression for centrifugal force is shown below as:-

F=\frac{m\times v^2}{r}

Where, m is the mass of the object = ?

v is the velocity of the object = 7.60 m/s

r is the radius

F is the force = 222 N

Diamter = 11.6 m

Radius = d/2 = 11.6 m/2 = 5.8 m

Applying the values in the above expression as:-

222=\frac{m\times {7.60}^2}{5.8}

57.76m=1287.6

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7 0
3 years ago
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