What is the difference between acids and strong acids?

If one of the reactants in a reaction is Na2O, what is known about the products?

const2013 [10]

D. The products will have at least 2 Na atoms and 1 O atom.

<h3>Further explanation</h3>

If we refer to the law of mass conservation, which states that

<em>In a closed system, the masses before and after the reaction are the same </em>

then the number of atoms in the reactance will be the same as the number of atoms in the product

In this problem it is known that Na₂O is one of the reactants so that the product of Na atoms and O atoms will at least equal the number of atoms in the bond, namely 2 Na and 1 O

Like an example of this Na₂O reaction:

Na₂O + H₂O ⇒ 2 NaOH

Na : left =2, right = 2

O : left=2, right = 2

4 0

3 years ago

Read 2 more answers

Mutations are more important to the evolution of a species because

EleoNora [17]

Answer: Mutations are important to the evolution of a species because is creates new DNA for a certain gene, creating a new allele.

Hope this helps!!! Good luck!!! ;)

8 0

3 years ago

What is the reactant(s) in the chemical equation below?

butalik [34]

Answer:

C. 3CO(g) + Fe2O3(s)

Explanation:

The substance(s) to the hath left of the arrow in a chemical equation art hath called reactants. A reactant is a substance yond is presenteth at the starteth of a chemical reaction. The substance(s) to the right of the arrow art hath called products. A product is a substance yond is presenteth at the endeth of a chemical reaction

So in this example, 3CO(g) + Fe2O3(s) art the reactants.

The 2Fe(S) + 3CO2(G) art the products.

Desire I holp! Has't a most wondrous day!

Hope I helped! Have a great day!

7 0

3 years ago

A student reacts 5.0 g of sodium with 10.0 g of chlorine and collect 5.24 g of sodium chloride. What is the percent yield of thi

Ede4ka [16]

Answer: The percent yield of this combination reaction is 41.3 %

Explanation : Given,

Mass of $Na$ = 5.0 g

Mass of $Cl_2$ = 10.0 g

Molar mass of $Na$ = 23 g/mol

Molar mass of $Cl_2$ = 71 g/mol

First we have to calculate the moles of $Na$ and $Cl_2$ .

$\text{Moles of }Na=\frac{\text{Given mass }Na}{\text{Molar mass }Na}$

$\text{Moles of }Na=\frac{5.0g}{23g/mol}=0.217mol$

and,

$\text{Moles of }Cl_2=\frac{\text{Given mass }Cl_2}{\text{Molar mass }Cl_2}$

$\text{Moles of }Cl_2=\frac{10.0g}{71g/mol}=0.141mol$

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation will be:

$2Na+Cl_2\rightarrow 2NaCl$

From the balanced reaction we conclude that

As, 2 mole of $Na$ react with 1 mole of $Cl_2$

So, 0.217 moles of $Na$ react with $\frac{0.217}{2}=0.108$ moles of $Cl_2$

From this we conclude that, $Cl_2$ is an excess reagent because the given moles are greater than the required moles and $Na$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $NaCl$

From the reaction, we conclude that

As, 2 mole of $Na$ react to give 2 mole of $NaCl$

So, 0.217 mole of $HCl$ react to give 0.217 mole of $NaCl$

Now we have to calculate the mass of $NaCl$

$\text{ Mass of }NaCl=\text{ Moles of }NaCl\times \text{ Molar mass of }NaCl$

Molar mass of $NaCl$ = 58.5 g/mole

$\text{ Mass of }NaCl=(0.217moles)\times (58.5g/mole)=12.7g$

Now we have to calculate the percent yield of this reaction.

Percent yield = $\frac{\text{Actual yield}}{\text{Theoretical yield}}\times 100$

Actual yield = 5.24 g

Theoretical yield = 12.7 g

Percent yield = $\frac{5.24g}{12.7g}\times 100$

Percent yield = 41.3 %

Therefore, the percent yield of this combination reaction is 41.3 %

4 0

3 years ago

Equation of ethane to ethanoic acid

VMariaS [17]

Feb 16, 2012 ... How do you convert ethane to ethanoic acid? (with equation please). First you chlorinate it in presence of light. C2H6 + Cl2 ---hv -> C2H5Cl + ...

Preparation of ethanoic acid from ethane This free online course covers the preparation of ethanoic acid from ethane. The Contents tab displays all the lessons ...

he formation of the aldehyde is shown by the simplified equation: ... Note: The equation for the conversion of ethanol to ethanoic acid is worked out in detail ... Starting from ethanenitrile, you would therefore get a solution containing ethanoate ... Mar 3, 2012 ... As well as using a normal type of molecular formula to describe an organic .... In ethane the carbon atoms have the maximum number of hydrogen atoms bonded .... e.g. ethanoic acid and ethanol will produce ethyl ethanoate,.

8 0

3 years ago