6.2 grams of CO2 = 1.408786739226764 moles
Answer:
The answer is 3-Phenylpropanoic acid (see attached structure)
Explanation:
From spectral data:
3005 cm-1 ⇒ carboxylic acid (broad band)
1670 cm-1 ⇒ C=C
1603 cm-1 ⇒ Aromatic C-C bond
H NMR frequency at 2.6 ppm, singlet, ⇒ OH with no surrounding protons, possible deshielding (clearer investigation of spectrum would be expedient).
Hence, our C9H10O2 compound has an aromatic ring and carboxylic acid group attached to it.
B is gas
The chemical element krypton is classed as a noble gas and a nonmetal.
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Answer: 147 mL
Explanation:
<u>Given:</u>
Molarity of the sodium bromide (NaBr) solution (M1) = 1.75 M
Volume of the solution (V1) = 84 mL
Molarity of the diluted NaBr solution (M2) = 1 M
Using the dilution formula to solve for V2:

Therefore, the new volume of the solution is 147 mL